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Did I do this right? let me know if I did anything wrong. It is about writing empirical formulas
1 answer:
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Answer:
Two moles.
Explanation:
Sulphuric (sulfuric) acid is a diprotic acid. When one mole of
molecules dissolve in water, two moles of
ions would be produced.
.
On the other hand, sodium hydroxide is a monoprotic base. When one mole of
formula units dissolve in water, only one mole of hydroxide ions
would be produced.
.
Note that and
react at a one-to-one ratio:
.
As a result, it would take of
to react with the
of
that was released when
of
is dissolved in water. Since one mole of
formula units could produce only one mole of
, it would take
of
formula units to produce that
of
for reacting with
of
.
The percent yield of copper hydroxide is 84%
<h3>Stoichiometry</h3>From the question, we are to determine the percent yield of copper hydroxide
First, we will determine the theoretical mass
From the given balanced chemical equation, we have
Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃
This means,
1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide
Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide
The theoretical number of moles of copper hydroxide that is produced is 0.05 mole
Now, for the theoretical mass
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of copper hydroxide = 97.56 g/mol
Then,
Theoretical mass = 0.05 × 97.56
Theoretical mass of copper of hydroxide produced is = 4.878 g
Now, for the percent yield of copper hydroxide
Percent yield is given by the formula,
Then,
Hence, the percent yield of copper hydroxide is 84%.
Learn more on Stoichiometry here: brainly.com/question/9372758