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leonid [27]
3 years ago
8

He reaction produces 1.6 g of gas in 30 seconds.Calculate the mean rate of the reaction in the first 30 seconds.Use the equation

:
Chemistry
1 answer:
devlian [24]3 years ago
5 0

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

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What decides if an atom will be a cation or an anion?
JulijaS [17]

The loss or gain of electrons

Explanation:

The loss or gain of electrons determines if an atom will become a cation or anion.

A cation is a positively charge ion

An anion is a negatively charged ion.

In an atom, we have sub-atomic particles:

 Protons are the positively charged particles

 Electrons are negatively charged

  Neutrons carry no charges

Only electrons can be lost or gained in chemical processes that forms cations and anions.

When a neutral atom gains electron, it has more electrons than protons. This makes it negatively charged and we call it an anion.

When a neutral atom loses an electron, the number of protons is more. We call it a cation.

Learn more:

Cations brainly.com/question/4670413

#learnwithBrainly

7 0
3 years ago
If we wanted to add to the Venn diagram to reflect the Arrhenius acid-base theory, which statements would be MOST appropriate? A
Arlecino [84]

Answer:b

Explanation:

4 0
3 years ago
What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
lisabon 2012 [21]

Theoretical yield of Al₂O₃: 1.50 mol.

<h3>Explanation</h3>

2 \; \text{Al} + \dfrac{3}{2} \; \text{O}_2 \to {\bf 1} \; \text{Al}_2\text{O}_3;

4 \; \text{Al} + 3 \; \text{O}_2 \to 2 \; \text{Al}_2\text{O}_3 \; \textit{Balanced}.

How many moles of aluminum oxide formula units will be produced <em>if</em> aluminum is the limiting reactant?

Aluminum reacts to aluminum oxide at a two-to-one ratio.

3.00 \times \dfrac{1}{2} = 1.50 \; \text{mol}.

As a result, 3.00 moles of aluminum will give rise to 1.50 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced <em>if</em> oxygen is the limiting reactant?

Oxygen reacts to produce aluminum oxide at a three-to-two ratio.

2.55 \times \dfrac{2}{3} = 1.70 \; \text{mol}

As a result, 2.55 moles of oxygen will give rise to 1.70 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced?

Aluminum is the limiting reactant. Only 1.50 moles of aluminum oxide formula units will be produced. 1.70 moles isn't feasible since aluminum would run out by the time 1.50 moles was produced.

4 0
3 years ago
What is the total number of valence electrons un xenon(xe)
Ber [7]

Answer:

8

Explanation:

Hope this helps you :)

6 0
3 years ago
What are sister chromatids
Pavel [41]
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