Ask question

Ask question

All categories

3 years ago

5

For which of the following conversions does the value of the conversion factor depend upon the formula of the substance?

2 answers:

trasher [3.6K]3 years ago

5 0

The answer is: C) mass of any substance to moles.

To converte mass to amount of substances, mass must be divided by molar mass (n = m ÷ M).

Molar mass M represent the mass of a substance divided by the amount of substance. If the formula is not correct, amount of substance is not correct.

For example, calculate molar mass of iron(II) chloride:

Atomic mass of iron is 55.8 g/mol.

Atomic mass of chlorine is 35.5 g/mol.

If compound is FeCl, molar mass would be 55,8 g/mol + 35,5 g/mol = 91,3 g/mlo, that is not correct.

If compound is FeCl₂, malar mass of compound would be:

55,8 g/mol + 2·35,5 g/mol = 126,8 g/mol, that is correct.

pochemuha3 years ago

3 0

For which of the following conversions does the value of the conversion factor depend upon the formula of the substance?

The answer is C

You might be interested in

Alex777 [14]

Answer:

............................................

8 0

2 years ago

Read 2 more answers

Consider the intermediate chemical reactions. 2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one ha

DochEvi [55]

<u>Answer:</u> When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

$CaO(s)+CO_2\rightarrow CaCO_3(s)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)$ $\Delta H_1=-812.8kJ$

(2) $2Ca(s)+O_2(g)\rightarrow 2CaO(s)$ $\Delta H_2=-1269kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]$

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

3 0

3 years ago

True or false all countries are legally bound to survey and monitor for disease within their bodies

ra1l [238]

Answer:

False..........

7 0

3 years ago

Can someone please help me with this asap, it’s due today please help me

hammer [34]

Answer:

lol I hate chemical but let me give some advice

Explanation:

Please go on Khan Academy or look at your notes and I promise you can figure out! Seriously, I am trying to be helpful not like the annoying teacher that says "figure it out"

7 0

3 years ago

Estimate the optimal number of neutrons for a nucleus containing 70 protons.

DochEvi [55]

Atomic number 70

weight 173

number of neutron = weight - Atomic number

= 173 -70

=103

6 0

3 years ago

Read 2 more answers