Answer:
2NaClO₄ (aq) + Ni(NO₃)₂ (aq) → 2NaNO₃ (aq) + Ni(ClO₄)₂ (aq)
No reaction
Explanation:
NaClO₄ → Sodium perchlorate
Ni(NO₃)₂ → Nickel (II) nitrate
All the salts from nitrate are soluble salts
All the salts from perchlorate are soluble salts except for the KClO₄
Answer:
Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F
Explanation:
At the given interval, concentration of HI = 
Concentration of 
= 
Concentration of 
= 
Reaction quotient,
, for this reaction = ![\frac{[H_{2}][I_{2}]}{[HI]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D%7B%5BHI%5D%5E%7B2%7D%7D)
species inside third bracket represents concentrations at the given interval.
So, 
So, the reaction is not at equilibrium.
As 
therefore reaction must run in reverse direction to reduce and make it equal to 
. That means HI(g) must be produced and must be consumed.
Answer:
on each side of the salt bridge, which is represented by a double vertical line
Explanation:
While writing a cell notation, the general convention is; anode || cathode. The anode and the cathode are separated by a double line. The anode is written on the lefthand side while the cathode is written on the righthand side.
The cell notation is a shorthand representation of a cell, hence any electrochemical cell can easily be produced based on its cell diagram.
Answer:
λ = 6.5604 x 1016 nm
Explanation:
Given Data:
The energy of the red line in Hydrogen Spectra = 3.03 x 10-19
Formula to calculate Wave length
E= hv
Where E is Energy
h is Planks Constant = 6.626 x 10–34 J s
v is frequency
In turn
v= c/ λ
where c is speed of light = 3.00 x 108 m s–1
λ is wavelength = to find
Solution:
Formula to be Used:
E= hv………………………… (1)
Putting the value v in equation 1
E= h c/ λ…………………… (2)
Put the value in equation 2
3.03 x 10-19 J = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) / λ ……………………….(3)
By rearranging equation 3
λ = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) /3.03 x 10-19 J
λ = 6.5604 x 107 m
The answer is in “m”
So we have to convert it into nm
So for this to convert “m” to “nm” multiply the answer with 109
λ = 6.5604 x 107 x 109
λ = 6.5604 x 1016 nm
Answer:
7.35 - 7.45
Explanation:
The pH scale ranges from 0 (strongly acidic) to 14 (strongly basic or alkaline). A pH of 7.0, in the middle of this scale, is neutral. Blood is normally slightly basic, with a normal pH range of about 7.35 to 7.45. Usually, the body maintains the pH of blood close to 7.40.
Hope this helps
