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ladessa [460]
3 years ago
11

Does anyone know number #1

Physics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer:

He can use the hot plate to heat the substances and use the thermometer to measure the temp and use the stopwatch to make sure they are heated for the same amount of time.

Explanation:

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A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa
Alik [6]

To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

The electric field is

E = \frac{\lambda}{2\pi \epsilon_0 r}

Here,

\lambda= Linear charge density

\epsilon_0 = Permittivity of free space

r = Distance

The linear charge density can be written as,

Linear charge density is given as

\lambda = \frac{q}{L}

Replacing,

E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}

E = \frac{q}{2\pi \epsilon_0 rL}

The initial and final electric Force can be written as function of the charge and the electric field as

F_i = E_i q

F_f = E_f q

If we replace the value for the electric field we have,

F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})

Length is one third at the end, then

F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})

The ratio of the force is

\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}

\frac{F_f}{F_i} = 3

Therefore the required ratio is 3

7 0
3 years ago
10. Calculate A ramp is
inna [77]

Answer: 3.33

Explanation:

MA = De/Dr

MA = 5.0/1.5

MA= 3.33

5 0
4 years ago
A resistor, inductor, and a battery are arranged in a circuit. The circuit has an inductance of L = 1 H and a resistance of 1.4
shtirl [24]

Answer:

\tau \approx 7.14 \times 10^{-4}s \approx0.714ms

Explanation:

In a LC circuit The time constant τ is the time necessary for 60% of the total current (maximum current), pass through the inductor after a direct voltage source has been connected to it. The time constant can be calculated as follows:

\tau =\frac{L}{R}

Therefore, the time needed for the current to reach a fraction f = 0.6(60%) of its maximum value is:

\tau =\frac{1}{1.4\times 10^{3}} =7.142857143 \times 10^{-4} \approx7.14 \times 10^{-4}s

8 0
4 years ago
11. Reflecting telescopes are popular because they're _______ than a refracting telescope.
Anon25 [30]
I do not know what the school expects as an answer, but advantage of reflecting telescopes is that there is only one major reflecting surface, so it is quite easy to create a 6 or 8 inch telescope by an amateur, after adding on a prism and an eyepiece.  (a microscope eyepiece could be used).
MY answer would be "easier to build".  (it still takes tens of hours to grind and polish the single plane surface to a parabolic surface).

Electromagnetic waves all have the same velocity in the same medium.  However, since frequencies vary widely, so do wavelengths.

4 0
3 years ago
Read 2 more answers
The volume of a cantaloupe is approximated by Upper V equals four thirds pi font size decreased by 5 r cubedV= 4 3π r3. The radi
GuDViN [60]

Answer:

68.445 cm³/s

Explanation:

Given:

Volume, V = \frac{4}{3}\pi r^3

radius = 5.85 cm

Growth rate of radius = 0.5 cm/week

now

differentiating the volume with respect to time 't', we get:

\frac{dV}{dt}=\frac{d(\frac{4}{3}\pi r^3)}{dt}

or

\frac{dV}{dt}=(\frac{4}{3}\pi )3r^2\frac{dr}{dt}

now, substituting the value of r (i.e at r = 5.85cm) in the above equation, we get:

\frac{dV}{dt}=4\pi 5.85^2\times 0.5

or

\frac{dV}{dt}=68.445cm^3/s

hence, the rate of change of volume at r = 5.85cm is 68.445 cm³/s

6 0
4 years ago
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