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stealth61 [152]
3 years ago
10

What are all the invertebrates with a large foot

Physics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

Explanation:

Bobbitt worm ( Eunice aphroditois). This segmented polychaete marine worm can attain lengths of 10 feet. It bristles...

Goliath beetle ( Goliathus species). African goliath beetle ( Goliathus giganteus ). Five species of goliath beetle...

atlas moth ( Attacus atlas). Stop and rest your eyes on this lovely...

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A 60-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 3.0 N for a distance of 7.0 m.
Schach [20]

Answer:

Explanation:

Kinetic energy generated = work done by force = force x displacement

= 3 x 7 = 21 J

5 0
3 years ago
1)what is the momentum of a 40,000,000kg tanker traveling at 5 m/s?
Fittoniya [83]

Answer:

1)4*10^7 * 5= 2*10^8

2)50/10=5

5 0
3 years ago
When we greatly dim the light used in a double-slit experiment, we don’t simply get a dimmer interference pattern. What do we ge
maw [93]

Answer:

....... ....................

8 0
3 years ago
tourist travels 1500 miles using two planes. The second plane averages 50 miles per hour faster than the first plane. The touris
Genrish500 [490]

Answer

given,

tourist travels = 1500 miles

second plane averages 50 miles per hour faster than the first plane.

x = y + 50

The tourist uses the slower plane for the first 500 and the faster plane for the next 1000 miles.

total flying time = 6.5 hours

\dfrac{500}{y} + \dfrac{1000}{x} = 6.5

\dfrac{500}{y} + \dfrac{1000}{y + 50} = 6.5

\dfrac{500(50 + y)+ 1000 y}{y(y + 50)} = 6.5

25000 + 600 y = 6.5 y^2 + 325 y

6.5 y^2 - 275 y - 25000 = 0

on solving equation

y = 86.67 mile/hr

x = 86.67 + 50

x = 136.67 mile/hr

8 0
3 years ago
The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su
balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

\rm  I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2  \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2}  \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0
2 years ago
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