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Dimas [21]
4 years ago
5

Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's

Physics
1 answer:
valentina_108 [34]4 years ago
7 0

Answer:

11.) g = 3.695 m/s^2

12.) g = 8.879 m/s^2

13.) E = 8127 N/C

Explanation:

11.) Given that the

Mercury mass M = 3.3 × 10^23kg

Radius r = 2.44 ×10^6 m

Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2

Gravitational field strength g can be calculated by using the formula below

g = GM/r^2

Substitutes all the parameters into the formula

g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2

g = 2.2×10^13/5.954×10^12

g = 3.695 m/s^2

12.) Given that the

Venus mass M = 4.87×10^24kg

Radius r = 6.05 × 10^6 m

Using the same formula for gravitational field strength g

g = GM/R2

Substitute all the parameters into the formula

g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2

g = 3.25×10^14/3.66×10^13

g = 8.879 m/s^2

13.) Given that the

Charge = 2.26 nC = 2.26×10^-9

Distance d = 0.05m

Electric field strength E can be calculated by using the formula below

E = Kq/d^2

Where

K = electrostatic constant 8.99 × 10^9 Nm2/C2

Substitutes all the parameters into the formula

E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2

E = 20.3174/2.5×10^-3

E = 8126.96 N/C

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A train moves with a constant velocity for 15s for 155m. How fast is the train moving?
bonufazy [111]

Answer: 10.3m/s

Explanation:

In theory and for a constant velocity the physics expression states that:

Eq(1):  distance  = velocity times time <=> d = v*t    for v=constant.

If we solve Eq (1) for the velocity (v) we obtain:

Eq(2):  velocity  = distance divided by time <=> v = d/t

Substituting the known values for t=15s and d=155m we get:

v = 155 / 15 <=> v = 10.3

5 0
3 years ago
Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor.
irinina [24]
So if the formula for work is force times displacement times cosine(theta), you'd plug in the numbers

100x5 (since there's no angle in the problem, cosine(theta) isn't used

100x5 = 500

So the answer would be B.

Hope that helps!
6 0
3 years ago
Read 2 more answers
What would the density of an object be with a mass of 0.8g
True [87]

The density of the object is 0.032 g/cm^3.

<h3>What is density?</h3>

The term density means the ratio of the mass to the volume of an object. Now we know that when an object is dense that it would sink to the bottom of a fluid.

Now given that;

Mass = 0.8 g

volume= 25 cm^3

Density = mass/volume

Density =  0.8 g / 25 cm^3

= 0.032 g/cm^3

Learn more about density:brainly.com/question/15164682

#SPJ1

MISSING PARTS

What is the density of an object having a mass of

0.8g and a volume of 25cm^3

4 0
2 years ago
What would change if the wave had higher frequency
lara [203]

If the frequency of a wave increases and it stays in the same medium, then its <em>wavelength decreases</em>.

8 0
3 years ago
(pleases show work)
Feliz [49]

a. 46 m/s east

The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:

v=u+at

where

v is the velocity calculated at time t

u is the initial velocity

a is the acceleration

The jet in the problem has, taking east as positive direction:

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

Substituting t = 10 s, we find the final velocity of the jet:

v=16 + (3)(10)=46 m/s

And since the result is positive, the direction is east.

b. 310 m

The displacement of the jet can be found using another suvat equation

s=ut+\frac{1}{2}at^2

where

s is the displacement

u is the initial velocity

a is the acceleration

t is the time

For the jet in this problem,

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

t = 10 s is the time

Substituting into the equation,

s=(16)(10)+\frac{1}{2}(3)(10)^2=310 m

4 0
3 years ago
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