Question

a 0.0818 kg salt shaker on a rotating table feels an inward frictional force of 0.108 N when it is moving 0.333m/s. what is the radius of its motion?(unit=m)

Answer 1

Answer:

The required radius of its motion is $0.084m$.

Explanation:

The formula for calculating the required  radius of its motion is given by

$F = (mv^2)/r$

Where m= mass  

V= moving velocity

F=frictional force

r = radius of its motion

Then the required radius of its motion is given by

$r =(mv^2)/F$

Given that

mas =0.0818 kg

Frictional force= 0.108 N

Moving with Velocity of  = 0.333 m/s

radius of its motion = $\frac{[0.0818 kg \times (0.333 m/s)^2]}{0.108 N}$

Hence the required radius of its motion is r = $8.4 cm=0.084m$