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3 years ago

One number exceeds another by 44. the sum of the numbers is 24. what are the numbers?

Mathematics

1 answer:

baherus [9]3 years ago

4 0

Let, the numbers = x,y

x+y= 24 1st eqn

x-y = 44 2nd eqn

24-y-y = 44

-2y = 44-24

y = 20/-2 = -10

substitute that in equation 1st x = 24+10 = 34

so, the numbers would be 34 & -10

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Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

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$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

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The expression cannot be further simplified.

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3 years ago

One number exceeds another by 44. the sum of the numbers is 24. what are the​ numbers?

One number exceeds another by 44. the sum of the numbers is 24. what are the numbers?