Answer:
There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.
6/3 = 3+ 0.5
The process would be different if some values are the same values already on the chart total of each class.
ie) 20 31 14 22 20 31
small data like this below you can rearrange
14 20 20 22 31 31
and see that 21 is the correct value
as there are even numbers, so we choose 20 , 22
and select the middle value = 21
Step-by-step explanation:
If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.
I may be wrong, I think I remember how to do this. A straight line has an angle of 180, so y would be 133, making the area 55571.63u. (u = whatever unit is measuring the circle.) If x = 1/20 of the area, then the red area = 2,778.5u or 2,779u. I hope this helps, but I honestly don't remember how I would find x, and I don't want you to get the question wrong.
9514 1404 393
Answer:
16) No
17) (c)
Step-by-step explanation:
For a lot of multiple-choice matrix problems, a simple test is all that is needed to determine the correct answer.
16) The determinant of A is (-2)(-2) -(2)(-3) = 10. So, we expect to see values in the inverse matrix that are 0.2 and 0.3. Alas, they're not there. The matrices are not inverses.
A^-1 = [[-.2, .3][-.2, -.2]]
__
17) The matrices are both 3×3, so their product is possible (eliminates choice D). The upper left term is different among the answer choices, so we can determine the correct one by computing that term only.
BA=C
c11 = (5)(1) +(7)(5) +(3)(-1) = 5 +35 -3 = 37
This matches the third choice (C).
If you use a calculator to compute the full matrix product, it matches choice C in all details.
Answer:
b .150 I hope it is. I'm positive
Yes you do and what grade are you in and do you need help answering these questions
