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3 years ago

When a test instrument is calibrated, does its accuracy, precision, or reliability improve?

Chemistry

1 answer:

My name is Ann [436]3 years ago

8 0

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

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What accounts for the large increase in volume when sugar burns?

Dimas [21]

I don’t know type it up yourself

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3 years ago

Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg C. The densities of hexane and octane are 0.655 g/cm3 an

avanturin [10]

Answer:

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L= $1000 cm^3$

Density of octane= d = $0.703 g/cm^3$

Mass of octane ,m= $d\times v=0.703 g/cm^3\times 1000 cm^3=703 g$

Moles of octane = $\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol$

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

$55\%=\frac{6.166 mol}{\text{Total moles}}\times 100$

Total moles = 11.212 mol

Moles of hexane :

$45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100$

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D = $0.655 g/cm^3$

Volume of hexane = V

$V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L$

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

5 0

3 years ago

Justin mixed two clear liquids together during an experiment and made the following observations: The mixed liquids decreased in

kvasek [131]

Answer:

Explanation:

A chemical change occurred, and this caused the liquid’s physical properties to change.

when we read her experiment we can see that color changed to blue, it is because new products are formed. And the temperature cause this.

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3 years ago

What is the molarity of a solution that is prepared by adding 3 moles of CaSO4 in 1.5 L of water?

blondinia [14]

Answer:

$[CaSO_4] = 2 mol/L$

Explanation:

$[CaSO_4] = \frac{3 mol}{1.5 L} = 2 mol/L$

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2 years ago

Which one of the following compounds is diiodine heptoxide

MaRussiya [10]

Answer:

Diatomic molecules are molecules composed of only two atoms, of the same or different chemical elements. The prefix di- is of Greek origin, meaning "two

Explanation:

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3 years ago