All categories

3 years ago

When a test instrument is calibrated, does its accuracy, precision, or reliability improve?

Chemistry

1 answer:

My name is Ann [436]3 years ago

8 0

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

You might be interested in

What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?

Elina [12.6K]

Answer:

ΔG = 18KJ/mol

Explanation:

Given data:

ΔS = 0.09 Kj/mol.K

ΔH = 27 KJ/mol

Temperature = 100 K

ΔG = ?

Solution:

Formula:

ΔG = ΔH - TΔS

ΔH = enthalpy

ΔS = entropy

by putting values,

ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)

ΔG = 27 KJ/mol - 9 KJ/mol

ΔG = 18KJ/mol

7 0

2 years ago

A 475 cm3 sample of gas at standard temperature and pressure is allowed to expand until it occupies a

Andrej [43]

The final temperature : 345 K

<h3> Further explanation </h3>

Given

475 cm³ initial volume

600 cm³ final volume

Required

The final temperature

Solution

At standard temperature and pressure , T = 273 K and 1 atm

Charles's Law :

When the gas pressure is kept constant, the gas volume is proportional to the temperature

V₁/T₁=V₂/T₂

Input the value :

T₂=(V₂T₁)/V₁

T₂=(600 x 273)/475

T₂=345 K

4 0

2 years ago

Which of these is NOT a reason that scientists do experiments?

deff fn [24]

Design a new procedure

5 0

3 years ago

Read 2 more answers

How many grams of NH3 can be produced from the reaction of 28g of N2 and 25g of H2?

Reika [66]

N2<span> + 3H</span>2<span> = 2NH</span><span>3
so, NH3 = (N2 + 3H2)/ 2
= (28g + 3*25g)/2
= 51.5g</span>

4 0

2 years ago

14. Which of the following is produced when propane (C3H8) is combusted completely? (2 points)

Ymorist [56]

The following is produced when propane (C₃H₈) is combusted completely : H₂O

<h3>Further explanation </h3>

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (especially alkanes) $\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}$

For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :

C₃H₈+5O₂⇒3CO₂+4H₂O

The products of combustion : CO₂ and H₂O

7 0

2 years ago