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Svetllana [295]
3 years ago
15

assume that for the pH 9.2 phenolphthalein sample, you used half as much phenolphthalein solution (i.e your sample is 9 ml buffe

r, 0.5 ml phenophthalein solution and 0.5 ml water). what should happen to the value of Kc you determine?
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Explanation:

It is given that pH is equal to 9.2. So, we will calculate the value of pK_{a} as follows.

        pH = pK_{a} + log \frac{[H_{3}O^{+}]}{[\text{solution}]}

Putting the given values into the above formula as follows.

    pH = pK_{a} + log \frac{[H_{3}O^{+}]}{[\text{solution}]}

      pK_{a} = pH - log \frac{\frac{1}{0.5}}{\frac{1}{10}}

                  = 7.9

             K_{a} = 10^{7.9}

                       = 1.26 \times 10^{-8}

Since, the value of K_{a} comes out to be positive. This means that there will occur an increase in the value of K_{a} or K_{c}.

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