Answer:
t = 4.5
Step-by-step explanation:
1.8 = 0.4(t) solve for t
Answer:
it looks like you already have the answer but the answer would be slope as -1/3 and y intercept as -6
Answer:
75.44 Square Inches
Step-by-step explanation:
The diagram of the problem is produced and attached.
To determine the area of the cleaned sector:
Let the radius of the larger sector be R
Let the radius of the smaller sector be r
Area of the larger sector 
Area of the smaller sector 
Area of shaded part =Area of the larger sector-Area of the smaller sector

From the diagram, R=10 Inch, r=10-7=3 Inch, 
Therefore, Area of the sector cleaned

9514 1404 393
Answer:
D. Both functions are decreasing at the same average rate on that interval
Step-by-step explanation:
The dashed lines on the attached graph of the two functions (f in red, g in purple) represent the average rate of change of each function on the interval. The lines are parallel, because the average rate of change is the same for each of the functions on that interval.
__
Function f decreases by 60 units from f(0) = 64 to f(4) = 4 on the interval x = [0, 4]. Function g decreases by 60 units from g(0) = 75 to g(4) = 15 on the same interval. The average rate of change is the amount of decrease divided by the interval width. Those values are the same for both functions.