<u>Answer:</u> The moles of oxygen and carbon dioxide in air is
and
respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of atmosphere = 
Average molar mass of atmosphere = 28.96 g/mol
Putting values in above equation, we get:

We know that:
Percent of oxygen in air = 21 %
Percent of carbon dioxide in air = 0.0415 %
Moles of oxygen in air = 
Moles of carbon dioxide in air = 
Hence, the moles of oxygen and carbon dioxide in air is
and
respectively
Solution :
A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.
We know,
In a standard cell,
the reduction half cell reaction is :

The oxidation half ell reaction :

Thus the complete reaction of the cell is :

cell = 
Answer:
i think the answer is letter C. From 35°c to 45°c
Explanation:
sorry if it is wrong
Answer:
56.82 Kg
Explanation:
Given data:
1 Kg = 2.20 lbs
Number of kilogram in 125 lbs = ?
Solution:
lbs is used for pound. lb is abbreviation of libra. It is Latin word meaning balance.
Both kilogram and pounds are units of mass. Pound is smaller unit than kilogram.
one Kg = 2.20 lbs
Number of kg in 125 lbs:
125 lbs × 1 Kg/2.20 lbs
125 lbs.Kg/2.20 lbs
56.82 Kg