Below are the answers:
1.b - cfcs
2.d - <span>carbon dioxide,smog,acid rain. </span>
3.a - <span> laws and treaties that limit or ban pollutants</span>
4.c - <span>burning leaves and brush
</span>
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Answer:
C + O2 ⇒ CO2
mole of O2: 18.6/32=0.58125= mole of CO2
⇒ gram of CO2: 0.58125*(12+32)=25.575
Explanation:
The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
Answer:
= 654.5 g NaNO3
Explanation:
Molarity = Moles/ volume
Volume = 3.5 L
Molarity = 2.2 M
Therefore;
Moles = Molarity × volume
= 3.5 L × 2.2 M
= 7.7 moles
But 1 mole of NaNO3 is 85 g/mol
Mass of NaNO3 = 85 g/mole × 7.7 moles
= 654.5 g NaNO3
No he does not
Hopes it helped