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tino4ka555 [31]
3 years ago
13

A chemical process dissolves 500 milligrams of iron oxide every 20 minutes. How long would it take this reaction to dissolve 2 l

bs of iron oxide?
Chemistry
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

36290 min = 604.8 hr.

Explanation:

  • Knowing that:

1 lbs = 453.59237 grams.

∴ 2 lbs = 907.18474 grams.

<em><u>Using cross multiplication:</u></em>

500 mg of iron oxide dissolved → 20 minutes.

907184.74 mg of iron oxide dissolved → ??? minutes.

<em>∴ The time needed to dissolve 2 lbs of iron oxide =</em> (907184.74 mg)(20 min)/(500 mg) = <em>36290 min = 604.8 hr.</em>

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allochka39001 [22]

Answer:

\large \boxed{\text{0.1767 mol/L}}$

Explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O  

(b) Moles of NaOH

\text{Moles of  NaOH} = \text{34.52 mL NaOH} \times \dfrac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

\text{Moles of H$_{3}$PO}_{4} = \text{13.26 mmol NaOH} \times\dfrac{\text{ 1 mmol H$_{3}$PO}_{4}}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H$_{3}$PO}_{4}

(d) Molar concentration of H₃PO₄

c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V} = \dfrac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol $\cdot$ L$^{-1}$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{0.1767 mol/L}}$}

7 0
3 years ago
The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 x 10^23 atoms in 1 mol. How many atoms are present in 48.60 g of
docker41 [41]
Atoms of Mg  =  mol  *  L
   
     mol of Mg =  \frac{MASS}{MOLAR  MASS}
 
                      =  \frac{48.60 g}{24.30 g / mol}
    
                      =  2 mol

∴ atoms of Mg  =  2 mol  *  ( 6.02  x  10²³)
                         =  1.204  x  10²⁴


6 0
4 years ago
Select the name of the element with a condensed ground-state electron configuration of [kr] 5s14d7.
Vilka [71]

elements have equal number of protons and neutrons

the condensed format is when the closest noble gas with the closest electron configuration is given, this closest noble gas atomic number should be lesser than the atoms atomic number

atomic number of Kr is 36

1 electron in 5s subshell and 7 electrons in 4d subshell.

there's a total of 36 + 1 + 7 = 44 electrons

atomic number of the atom is 44

element with atomic number 44 is Ruthenium - Ru

answer is Ru


7 0
3 years ago
Read 2 more answers
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