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Ostrovityanka [42]
3 years ago
8

Can someone please help as soon as possible

Chemistry
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

Explanation:

#1 2HCL and 2H20

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How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
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Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

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M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

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Question 21
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There are 2 moles of O stones present in 88 grams of CO2. Why? Well, we can find the amount of moles present in 88 grams of CO2 by dividing the mass by the molar mass. The mass of CO2 comes out to be 88 grams. The molar mass of CO2 comes out to be 44 grams. Because 88 is the mass of CO2 and 44 is the molar mass of CO2, we can divide 88 by 44 to identify that there are 2.0 moles of O atoms present in 88 grams of CO2.

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