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ratelena [41]
2 years ago
6

X - y = 2 and x + y = -6 find intersecting point and graph

Mathematics
1 answer:
yulyashka [42]2 years ago
5 0
Intersecting point 4,2 with slope of 1/2
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How many pears would each person get if 14 pears are shared among 4 people
12345 [234]
To answer this, you would divide 14 pears / 4 people. The answer would be 3 1/2 pears per person.

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PLEASE HELP EXPLAIN THIS!!!!!
Neko [114]

Answer:

Step-by-step explanation:

Look at the number and the angles

Multiple the angles all together that's how u find x

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Please help meeeeeeeeeee
Darina [25.2K]
If you need help for all 3 questions then ok.
Here’s what you need to do. If they give you a rectangular prism with a side length of #, that number is the length, width and height. I’ll help you for the first picture. They asked how many cubic blocks with a SIDE LENGTH of 1/7 in can fill in a cube with the SIDE LENGTH of 3/7 in. Here is your equation: (3/7 x 3/7 x 3/7) / (1/7 x 1/7 x 1/7). That’s how you solve it. (The slash stands for division.) Now do the same thing with the other pictures. They will ask you how many blocks with a side length of # can fill in a prism with the length, width, and height (or just a side length without saying the l, w and h.) Hopefully this helped! If I got it wrong or if you need help cause you didn’t get what I mean, let me know.

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3 years ago
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kherson [118]
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7 0
3 years ago
4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep
bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.92}{2} = 0.04

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.04 = 0.96, so Z = 1.88.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that \sigma = 2.2

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.88\frac{2.2}{\sqrt{n}}

\sqrt{n} = 1.88*2.2

(\sqrt{n})^2 = (1.88*2.2)^2

n = 17.1

Rounding up:

A sample of 18 is required.

3 0
3 years ago
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