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Lilit [14]
2 years ago
6

The formation of tert-butanol is described by the following chemical equation:

Chemistry
1 answer:
fomenos2 years ago
3 0

Answer:

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

Explanation:

This reaction involves;

First the ionization of the tertiary halide to firm a carbocation

Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol

First step;

(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

This second step completes the reaction mechanism.

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2 years ago
Consider the following intermediate chemical equations. When you form the final chemical equation, what should you do with CO? C
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Answer:

Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.

Explanation:

The CO appears twice hence in he intermediate reaction it only forms path of the enabling reagents and it further reacts to form the final product. Accounting for the CO in the intermediate reaction that undergoes further reaction will impact on the stoichiometry of the reaction.

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3 years ago
The equilibrium constant Kc for the reaction below is 0.00584 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentra
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Answer:

Explanation:

Given that:

The chemical equation for the reaction is:

             Br2(g)    ⇌  2Br(g)

Initially  0.0345M  0.0416M

Q_C = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416)^2}{(0.0345)}= 0.05016

Q_C =0.05016 >>> K_c(0.00584)

Thus, the given reaction will proceed in the  backward direction

 The I.C.E table is as follows:

                       Br2(g)    ⇌  2Br(g)

I               0.0345                 0.0416

C                 +x                        -2x

E             (0.0345+x)            (0.0416 -2x)

K_c = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416-2x)^2}{(0.0345+x)} = 0.00584

= 0.00173056 - 0.0832x - 0.0832x + 4x² = 0.00584 (0.0345 +x)

= 0.00173056 - 0.166x + 4x² = 2.0148× 10⁻⁴ + 0.00584x

= 0.00173056 - 2.0148× 10⁻⁴ - 0.166x - 0.00584x + 4x²

= 0.00152908  - 0.17184x + 4x²

Solving by using Quadratic formula

x = 0.03038 or 0.0126

For x = 0.03038

At equilibrium

[Br₂] = (0.0345 + 0.03038) = 0.06488 M

[Br] =  (0.0416 -2(0.03038)) = - 0.01916 M

Since we have a negative value for [Br], we discard the value for x

For x = 0.0126

At equilibrium

[Br₂] = (0.0345 + 0.0126) = 0.0471 M

[Br] =  (0.0416 -2(0.0126)) = 0.0164 M

4 0
2 years ago
Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
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Answer:

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Explanation:

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What is the end result of a nuclear fusion reaction?
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Answer:A.) molecule of atoms forms

Explanation:

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3 years ago
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