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Lilit [14]
2 years ago
6

The formation of tert-butanol is described by the following chemical equation:

Chemistry
1 answer:
fomenos2 years ago
3 0

Answer:

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

Explanation:

This reaction involves;

First the ionization of the tertiary halide to firm a carbocation

Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol

First step;

(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

This second step completes the reaction mechanism.

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✡ Answer: 1.23*10^2 ✡


- - Add a decimal at the end (to the right) and count till you get to the first number.
So now you have 1.23

- - Now you always want to times it by 10 to the power of how many times you moved it over, in this case, 2

Final answer: 1.23*10^2

✡Hope this helps✡


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In the reaction as follows: NH2- + CH3OH → NH3 + CH3O−, NH2- is the Brønsted-Lowry base.

BRØNSTED-LOWRY BASE:

  • According to Bronsted-Lowry definition of a base and acid, a base is substance that accepts an hydrogen ion or proton (H+) while an acid is a substance that donates a proton.

  • According to this reaction given as follows: NH2 + CH3OH → NH3+ CH3O-

  1. NH2- is a reactant that accepts a hydrogen ion (H+) to become NH3+
  2. NH3+CH3OH is a reactant that donates hydrogen ion (H+)

  • Since NH2- accepts a proton, this means that in the reaction as follows: NH2 + CH3OH → NH3 + CH3O−, NH2- is the Brønsted-Lowry base.

Learn more at: brainly.com/question/21736327?referrer=searchResults

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