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vichka [17]
3 years ago
10

SI unit for measuring distance is

Chemistry
1 answer:
MrMuchimi3 years ago
6 0
The SI unit for measuring distance is the meter.
I attached a table of SI measurements for you :)
Hope this helped!

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Explain why atoms would gain or lose electrons in order to resemble the elements in the particular group you named above. Consid
Leokris [45]

Answer:

The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.

Explanation:

I hope that helps

4 0
3 years ago
Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
RoseWind [281]

Answer:

M_{per}= 52.86

W_{per}=47.14

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

m_{met2}=150 kg * 0.7= 105 kg

m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0
3 years ago
Why are there more fossils of marine organism than of land organisms o dc
MatroZZZ [7]

Answer:

Three primary reasons. First, there is simply more water-covered places than dry ground places for the animals and plants to have lived. Second, the seas are much more crowded with the kinds of life that leave fossils than the land is. Third, the process that form fossils work very well under water.

Explanation:

4 0
3 years ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
Zepler [3.9K]
d_{1}=\frac{m}{V_{1}}\\\\&#10;V_{1}=395cm^{3}\\&#10;d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\&#10;d_{2}=\frac{m}{V_{2}}\\\\&#10;m=150,1g\\&#10;d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
8 0
3 years ago
What are the products of photosynthesis? A: C6H12O6 + 6H2O + 6O2 B: C6H12O6 + 3O2 + 6H2O C: C6H12O6 + 3O2 + 3H2O D: C3H6O3 + 6O2
erik [133]
A: C₆H₁₂O₆ + 6H₂O + 6O₂

6CO₂ + 12H₂O = C₆H₁₂O₆ + 6H₂O + 6O₂
8 0
3 years ago
Read 2 more answers
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