Question

A gas mixture containing He, Ne, and Ar exerts a pressure of 3.00 atm. What is the partial pressure of each gas present in the mixture if the ratio of moles of gases in the container is 3:2:1

Answer 1

Answer:

Partial pressure of He(P(He) = 1.5 atm.

Partial pressure of Ne(P(Ne) = 1 atm.

Partial pressure of Ar(P(Ar) = 0.5 atm.

Explanation:

According to Dalton law of partial pressure the sum of partial pressures of individual gases in a gaseous mixture is equivalent to the total pressure.

The partial pressure of a gas in a gaseous mixture is given by the product of the mole fraction and the total pressure.

Our gaseous mixture contains He, Ne, and Ar and the total pressure is 3 atm.

Since we are given the ratios of the gases in the mixture, we can calculate the partial pressure of each gas.

P(He) = 3/6 × 3 atm.

         = 1.5 atm.

P(Ne) = 2/6 × 3 atm.

        = 1 atm

P(Ar) = 1/6 × 3 atm.

        = 0.5 atm

Therefore, the partial pressures of gases He, Ne and Ar are 1.5 atm, 1 atm, and 0.5 atm respectively.