Answer:
-36
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sum of angle in a triangle = 180°
<A+<B+<C = 180
Given <B = 50°
Substituting into the formula
<A+50+<C = 180
<A+<C = 180-50
<A+<C = 130°
Since the ∆ABC is an acute triangle, the angles <A and <C must be angles less than 90° since acute angles are angles less than 90°
The possible values of <A and <C that will be acute and give a sum of 130° are;
∠A= 58° and ∠C= 72°
∠A= 80° and ∠C= 50°
∠A= 60° and ∠C= 70°
You can see that all the Angles are less than 90° and their sum is 130°
<span> a) F' = 6 sin(x^2) = 0
x^2 = pi
x = sqrt(pi)
b) Fmax = F(1) + integral [1, pi] f(x) dx = 9.7743 </span>
Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
Answer:
C
Step-by-step explanation:
Since the triangle is right with hypotenuse QR
Use Pythagoras' identity to solve for QR
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
QR² = 8² + (8 )²
= 64 + 192
= 256 ( take the square root of both sides )
QR = = 16