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Otrada [13]
3 years ago
8

How much energy is required to melt a 500. gram block of iron? The heat of vaporization is 6090 J/g and the heat of fusion is 24

7 J/g.
3.05x10 6 J
2.47x10 2 J
1.23x10 5 J
6.09x10 3 J
Chemistry
1 answer:
ki77a [65]3 years ago
4 0

Answer:

Heat required = 1.23×10⁵J

Explanation:

Given:

Mass (m) = 500 gram

Specific heat = 6,090 J/g

heat of fusion = 247 J/g.

Find:

Heat required

Computation:

Heat required = 247 J/g× 500 g

Heat required = 1.23×10⁵J

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Explanation:

Potential energy is the the relationship between work done height mass and acceleration due to gravity, because of this some objects also experience kinetic energy due to the factors mentioned above

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The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr
Zina [86]

Answer:

Kb = [OH⁻] . [C₃H₉NH⁺] / [ C₃H₉N ]

Explanation:

The equation for the reaction of trimethylamine when it is dissolved in water is:

C₃H₉N  +  H₂O ⇄ C₃H₉NH⁺ + OH⁻   Kb

1 mol of trimethylamine catches a proton from the water in order to produce trimethylamonium.

It is a base, because it give OH⁻ to the medium

Expression for Kb (Molar concentration)

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the polio virus is 25 nanometers in diameter. How many would fit across the head of a pin 2 millimeters in diameter
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3 years ago
Describe in detail how to prepare 500.0 mL of a 2.5 M calcium chloride solution. Calcium chloride is purchased as a solid. TO pi
antoniya [11.8K]

Answer:

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the solute gets completely soluble add more water up till the mark of 500 ml.

Explanation:

Concentration of calcium chloride = 2.5 M

Volume of the solution = 500.0 ml = 0.5000 L

Moles of calcium chloride = n

c=\frac{n}{V(L)}

n = moles of solute

c = concentration of solution

V = volume of the solution in L

2.5 M=\frac{n}{0.5000 L}

n=2.5 M\times 0.5000 L = 1.2500 mol

n=\frac{\text{Mass of calcium chloride}}{\text{Molar mass of calcium chloride}}

1.2500 mol=\frac{\text{Mass of calcium chloride}}{111 g/mol}

Mass of calcium chloride = 111 g/mol × 1.2500 mol = 138.75 g

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the the solute gets completely soluble add more water up till the mark of 500 ml.

4 0
3 years ago
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