Answer:
1.40 atm
Explanation:
To answer this question we can use<em> Gay-Lussac's law</em>, which states:
When volume and number of moles remain constant.
- T₁ = 23°C ⇒ 23+273.16 = 296.16 K
- T₂ = Boiling point of water = 100 °C ⇒ 100+273.16 = 373.16 K
We <u>put the known data in the equation and solve for P₂</u>:
- 1.11 atm * 373.16 K = P₂ * 296.16 K
Answer:
C3F7
'Tri' means 3
Tricarbon means 3 carbon
"Hepta" means 7
Fluoridez molecular formula is "F"
hence F7
Answer:
32000atm
Explanation:
Using Boyle's law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (
V2 = final volume (L)
According to the question below:
P1 = 160.0 atm
P2 = 3.0 atm
V1 = 600L
V2 = ?
Using P1V1 = P2V2
160 × 600 = 3 × V2
96000 = 3V2
V2 = 96000/3
V2 = 32000atm
Answer:
b) Phosphorus acid
Explanation:
To distinguish the type of acid of phosphorus with the oxidation state of +3, we need to be familiar with the chemical formula of each of the compounds:
Orthophosphoric acid H₃PO₄
Phosphorus acid H₃PO₃
Metaphosphoric acid HPO₃
Phyrophosphoric acid H₄P₂O₇
Now that we know the formula of the given compounds, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero:
Only phosphorus acid yielded an oxidation state of +3 for phosphorus in the compound.
H₃PO₃:
we know the oxidation state of H = +1
O = -2
The oxidation state of P is unknown. We can express this as an equation:
3(+1) + P + 3(-2) = 0
3 + P -6 = 0
P-3 = 0
P = +3
Resources found in lithosphere: gold and iron etc
Resources found in atmosphere: Water vapor, gases etc.
