Answer:
39 mol AgNO3
Explanation:
We have the equation 4HNO3 + 3Ag -----> 3AgNO3 + NO + 2H2O
We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )
We can calculate this by using mole ratio as well as dimensional analysis.
The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.
Using this we can create a table: The table is attached.
Breakdown of the table.
The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.
Im 76% sure there is only one which is the Vacuoles
Density will be mass/volume= 0.2/500 = 0.0004
Because some machine might not work and would give you the wrong answer
Answer: The volume occupied by 2.50 moles of
gas at STP is 56.0L
Explanation:
According to ideal gas equation:

P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 2.50
R = gas constant =
T =temperature =
(at STP)


Thus the volume occupied by 2.50 moles of
gas at STP is 56.0L