<span>A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's velocity will be the same. In a projectile motion the horizontal component of the velocity is said to be constant. Therefore, it will be equal to the initial velocity.</span>
Answer:
A I think im fairly certain
Step-by-step explanation:
We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
1/2 + 9/20 = 19/20
1/20 + 1/10 = 3/20
1/8 + 11/16 = 13/16
2/9 + 5/9 = 7/9
3/20 + 3/4 = 18/20 = 9/10
7/17 + 1/17 = 8/17
Answer:
Therefore, the probability is P=1/84.
Step-by-step explanation:
We have a bag contains 3 red and 6 white tokens. Tokens are randomly selected and removed one at a time until the bag is empty.
We conclude that in a bag have 9 tokens.
We calculate the probability that the red tokens are drawn consecutively.
We calculate the number of possible combinations:
Number of favorable combinations is 1.
Therefore, the probability is P=1/84.
