Answer:
45.7kj
Explanation:
To calculates the heats of reaction from heats of formation:
∆Hr=£∆Hp -£∆Hr
= £∆Hch3ChOH - £∆HCh2h2+h20
=(-235.1kj)-(+52.47kj/kg + (-241.8kj/kg)
∆H = 45.71kj/kg
Ma = 1.66 M
Va = 30.7 mL
Mb = 0.704 M
Vb = 16.7 mL
Using the law <span>of dilution :
</span>
Mf = Ma x Va + Mb x Vb / Va + Vb
Mf = 1.66 x 30.7 + 0.704 x 16.7 / 30.7 + 16.7
Mf = 50.962 + 11.7568 / 47.4
Mf = 62.7188 / 47.4
Mf = 1.323 M
hope this helps!
Answer:
Distance cover = 8 km
Explanation:
Given:
Speed of runner = 4 km/h
Time taken = 2 hour
Find:
Distance cover
Computation:
Distance = Speed x Time
Distance cover = Speed of runner x Time taken
Distance cover = 4 x 2
Distance cover = 8 km
Answer:
Explanation:
1. Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3
2. FeSO4 + 2 NaOH = Fe(OH)2 + Na2SO4
3. Fe(NO3)3 + 3 NaOH = Fe(OH)3 + 3 NaNO3
For the second part of 3 since it tells us NaOH is excess we dont care about it. We use our balanced equation 3 to get the correct molar ratios to solve this.
1.5mol Fe(NO3)3 x 3mol NaNO3/1mol Fe(NO3)3 x 84.99gNaNO3/1molNaNO3
= 382.455g NaNO3
Answer:
try hypocenter for the blank spot... hope this helps
Explanation:
