Humans! They inhale and Exhale Oxygen and Carbon Dioxide.
1mol N2 + 3mol H2 → 2mol NH3
<span>Because you are dealing with gases, at the same temperature and pressure you can say: </span>
<span>1volume N2 + 3 volumes H2 → 2 volumes NH3 </span>
<span>OR: 4 volumes reactants = 2 volumes products. </span>
<span>You have 1.9+5.7 = 7.6 volumes reactants, which must give 7.6/2 = 3.8 volumes of NH3 </span>
<span>Answer: 3.8 litres of NH3 will be formed</span>
Answer:
14 g.
Explanation:
- From the figure attached:
<em>the solubility of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC is </em><em>(66 g).</em>
When beaker containing 80 grams of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC.
<em>∴ The grams of the salt are undissolved, on the bottom of the beaker are </em><em>(14 g).</em>
Answer:
Percentage yield = 25%
Explanation:
Given data:
Moles of C₈H₁₈ = 4 mol
Moles of O₂ = 4 mol
Actual yield of CO₂ = 28.16 g
Percentage yield = ?
Solution:
Chemical equation:
2C₈H₁₈ + 25 O₂ → 16CO₂ + 18H₂O
Now we will compare the moles of CO₂ with O₂ and C₈H₁₈.
C₈H₁₈ : CO₂
2 : 16
4 : 16/2×4=32 mol
O₂ : CO₂
25 : 16
4 : 16/25×4=2.56 mol
Mass of CO₂:
Mass = number of moles× molar mass
Mass = 2.56 mol ×44 g/mol
Mass = 112.64 g
Percentage yield:
Percentage yield = Actual yield /theoretical yield × 100
Percentage yield = 28.16 g / 112.64 g× 100
Percentage yield = 0.25× 100
Percentage yield = 25%
