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dimulka [17.4K]
4 years ago
9

Living organisms all have dna and rna which are both

Chemistry
2 answers:
Luba_88 [7]4 years ago
7 0
DNA and rna are both nucleus acids
Vadim26 [7]4 years ago
5 0

Answer:

D

Explanation:

Hope this helps :D

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In the modern periodic table the elements are arranged in order of increasing atomic number.
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A sample of wood with a mass of 30 g has its
anzhelika [568]

Answer:

0.086J/g°C

Explanation:

The following data were obtained from the question:

Mass (M) = 30g

Initial temperature (T1) = 10°C

Final temperature (T2) = 45°C

Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C

Heat (Q) released = 90J

Specific heat capacity (C) of wood =..?

We can obtain the specific heat capacity of the wood as follow:

Q = MCΔT

90 = 30 x C x 35

Divide both side by 30 x 35

C = 90/(30 x 35)

C = 0.086J/g°C.

Therefore, the specific heat capacity of the wood is 0.086J/g°C.

5 0
3 years ago
Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790
sesenic [268]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

S(s)+O_2(g)\rightarrow SO_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)    \Delta H_1=-196kJ

(2) 2S(g)+3O_2(g)\rightarrow 2SO_3(g)     \Delta H_2=-790kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}

Putting values in above equation, we get:

\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ

Hence, the \Delta H^o_{rxn} for the reaction is -297 kJ.

8 0
3 years ago
What’s the answer ? and how did you get it ?
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