D. dormancy is the correct answer
Answer:
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Answer:
The volume increases by 100%.
Explanation:
<u>Step 1:</u> Data given
Number of moles ideal gas = 1 mol
Initial temperature = 305 K
Final temperature = 32°C + 273.15 = 305.15 K
Initial pressure = 2 atm
final pressure = 101 kPa = 0.996792 atm
R = gasconstant = doesn't change
V1 = initial volume
V2= the final volume
<u>Step 2: </u>Calculate volume of original gas
P*V = n*R*T
(P*V)/ T = constante
(P1 * V1) / T1 = (P2 * V2)/ T2
In this situation we have:
(2atm * V1)/ 305 = (0.996792 *V2) / 305.15
0.006557*V1 = 0.003266*V2
V2 = 2*V1
We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.
A compound has to be chemically bonded, however, air is not chemically bonded.
This can be proven by freezing air. By freezing air, it yields different liquids at different temperature. Liquid nitrogen has a different boiling point than liquid oxygen.
If air was a compound, they would all have a single boiling point and a single freezing point.
Hope this helps :)
