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gizmo_the_mogwai [7]
3 years ago
10

Heats of reaction calculated from bond energies and from heats of formation are often, but not always, close to each other.a. In

dustrial ethanol (CH3CH2OH) is produced by a catalytic reaction of ethylene (CH2=CH2) with water at high pressures and temperatures. Calculate ΔHºrxn for this gas-phase hydration of ethylene to ethanol, using bond energies and then using heats of formation.b. Ethylene glycol is produced b the catalytic oxidation of ethylene to ethylene oxide, which then reacts with water to form ethylene glycol:image from custom entry tool + H2O (l) = HOCH2CH2OH(l)The ΔHºrxn for this hydrolysis step, based on heats of formation, is -97 kJ/mol. Calculate ΔHºrxn for the hydrolysis using bond energies.c. Why are the two values relatively close for the hydration in part "a" but not close for the hydrolysis in part "b"?
Chemistry
1 answer:
postnew [5]3 years ago
8 0

Answer:

45.7kj

Explanation:

To calculates the heats of reaction from heats of formation:

∆Hr=£∆Hp -£∆Hr

= £∆Hch3ChOH - £∆HCh2h2+h20

=(-235.1kj)-(+52.47kj/kg + (-241.8kj/kg)

∆H = 45.71kj/kg

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Calculate the volume, in liters, occupied by 1.80 moles of H2 gas at STP.
masha68 [24]

Answer:

40.32L

Explanation:

So we know that 22.4 Liters is one mole of a gass so we can set up an equation to test that

1mole     1.8mole

_____ = _____

22.4L         x

and then cross multiply so you get 40.32L

3 0
3 years ago
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What type of force is produced when two objects are in contact, then move (or try to move) past each other?
Gnesinka [82]

Answer:

A. Frictional

Explanation:

Friction is the force created when two solid objects in contact try to move past each other.

3 0
4 years ago
Which describes an atom of actinium?
Basile [38]

Answer:

Actinium is a chemical element with the symbol Ac and atomic number 89. A soft, silvery-white radioactive metal, actinium reacts rapidly with oxygen and moisture in air forming a white coating of actinium oxide that prevents further oxidation.

3 0
3 years ago
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Mercuric oxide (HgO) is heated and forms liquid mercury (Hg) and oxygen (O2) gas. How would you characterize this reaction?
My name is Ann [436]

Answer:

Decomposition reaction.

Explanation:

Decomposition reaction -

It is the type of reaction, where a single entity breaks down into various products under the influence of some external factors , like heat and sunlight , is referred to as a decomposition reaction.

From the question,

The reaction is -

2 HgO  →  2 Hg + O₂

Hence ,

A single compound HgO breaks down to two entities , i.e. , Hg and  O₂.

             

7 0
4 years ago
A 60.0 mL solution of 0.112 M sulfurous acid (H2SO3) is titrated with 0.112 M NaOH. The pKa values of sulfurous acid are 1.857 (
djverab [1.8K]

Answer:

a)4.51

b) 9.96

Explanation:

Given:

NaOH = 0.112M

H2S03 = 0.112 M

V = 60 ml

H2S03 pKa1= 1.857

pKa2 = 7.172

a) to calculate pH at first equivalence point, we calculate the pH between pKa1 and pKa2 as it is in between.

Therefore, the half points will also be the middle point.

Solving, we have:

pH = (½)* pKa1 + pKa2

pH = (½) * (1.857 + 7.172)

= 4.51

Thus, pH at first equivalence point is 4.51

b) pH at second equivalence point:

We already know there is a presence of SO3-2, and it ionizes to form

SO3-2 + H2O <>HSO3- + OH-

Kb = \frac{[ HSO3-][0H-]}{SO3-2}

Kb = \frac{10^-^1^4}{10^-^7^.^1^7^2} = 1.49*10^-^7

[HSO3-] = x = [OH-]

mmol of SO3-2 = MV

= 0.112 * 60 = 6.72

We need to find the V of NaOh,

V of NaOh = (2 * mmol)/M

= (2 * 6.72)/0.122

= 120ml

For total V in equivalence point, we have:

60ml + 120ml = 180ml

[S03-2] = 6.72/120

= 0.056 M

Substituting for values gotten in the equation Kb=\frac{[HSO3-][OH-]}{[SO3-2]}

We noe have:

1.485*10^-^7=\frac{x*x}{(0.056-x)}

x = [OH-] = 9.11*10^-^5

pOH = -log(OH) = -log(9.11*10^-^5)

=4.04

pH = 14- pOH

= 14 - 4.04

= 9.96

The pH at second equivalence point is 9.96

4 0
3 years ago
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