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4 years ago

12

How do you compare numbers in a scientific notation?

2 answers:

Neporo4naja [7]4 years ago

8 0

You can think about two numbers written in logical documentation by taking a gander at their forces of 10. The number with the more noteworthy intensity of 10 will be the more prominent number. In the event that two numbers have a similar intensity of 10, at that point contrast the decimal numbers with decide the more noteworthy number.

Already paraphrased so no need to change anything !

Yuki888 [10]4 years ago

7 0

To compare two numbers given in scientific notation, first compare the exponents. The one with the greater exponent will be greater. If the exponent is the same, compare the two numbers that are being multiplied by comparing their decimals.

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1,200 plus what equals what??

Evgesh-ka [11]

Answer:

1,200+300=1,500

Step-by-step explanation:

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3 years ago

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If there are 19 successful outcomes in a sample with a size of 25, what is the sample proportion

alexandr1967 [171]

Answer: the answer is .76

Step-by-step explanation:

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3 years ago

Find the GCF.<br><br> 18c3 and 24c3

12345 [234]

Answer:

6c³

Step-by-step explanation:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

Now we show the common factors in bold:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

The common factor are:

2, 3, c, c, c

GCF = 2 × 3 × c × c × c = 6c³

6 0

3 years ago

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

3 years ago

Let p = log10 x, q = log10 y, and r = log10 z. (The 10s are base numbers.)

KatRina [158]

Answer:

(p / q^2 √r)

Just make x, y, z into p, q, r.

Very simple!

4 0

4 years ago