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Anettt [7]
3 years ago
12

At which approximate light intensity does the oxygen production begin to level off? a. 40% b. 60% c. 80% d. 100%

Physics
2 answers:
levacccp [35]3 years ago
8 0

Answer;

-40% or 40 percent

Explanation;

-The main factors affecting rate of photosynthesis are light intensity, carbon dioxide concentration and temperature.

-Without enough light, a plant cannot photosynthesize very quickly; even if there is plenty of water and carbon dioxide and a suitable temperature. Increasing the light intensity increases the rate of photosynthesis, until some other factor (a limiting factor) becomes in short supply.

-An increase in light intensity will produce an increase in the rate of photosynthesis until a level of light intensity is reached (normally 40%) above which the rate does not increase because the light saturation point has been reached and another factor (CO2 concentration or temperature) is limiting.

a_sh-v [17]3 years ago
4 0
The answer is a. 40 %

Light intensity affect the level of oxygen production through photosynthesis ( a process in which plants use water, carbon dioxide and other minerals they can found from the ground to produce oxygen) , this process started to level off at 40% light intensity
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Polonium, gallium,argon
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What is the Force in Newtons exerted by cart with a mass of 0.75 kg and an Acceleration of 6m/s2?
denis-greek [22]

Answer:

<h2>4.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.75 × 6 = 4.5

We have the final answer as

<h3>4.5 N</h3>

Hope this helps you

6 0
2 years ago
An Earth satellite is orbiting at a distance from the Earth’s surface equal to one Earth radius (4 000 miles). At this location,
trasher [3.6K]

Answer:

The acceleration due to gravity is \dfrac{1}{4} times the value of g at the Earth’s surface.

(D) is correct option.

Explanation:

Given that,

Radius = 4000 miles

We need to calculate the gravitational force at surface

Gravitational force on the mass m on the surface of the earth

At r = R

F=mg

mg=\dfrac{GmM}{R^2}....(I)

We need to calculate the gravitational force at height

Gravitational force on a mass m from the center of the earth,

At r = R + R = 2 R

F'=mg'

mg'=\dfrac{GmM}{4R^2}....(II)

Dividing equation (II) by equation (I)

\dfrac{mg'}{mg}=\dfrac{\dfrac{GmM}{4R^2}}{\dfrac{GmM}{R^2}}

\dfrac{g'}{g}=\dfrac{1}{4}

Hence, The acceleration due to gravity is \dfrac{1}{4} times the value of g at the Earth’s surface.

4 0
3 years ago
Question 2
Yakvenalex [24]

Answer:

B

Explanation:

6 0
2 years ago
Experts, ACE, Genius... can anybody calculate for the Reactions at supports A and B please? Will give brainliest! Given: fb = 30
dybincka [34]

Answer:

Support at Cy = 1.3 x 10³ k-N

Support at Ay = 200 k-N

Explanation:

given:

fb = 300 k-N/m

fc = 100 k-N/m

D = 300 k-N

L ab = 6 m

L bc = 6 m

L cd = 6 m

To get the reaction A or C.

take summation of moment either A or C.

<em><u>Support Cy:</u></em>

∑ M at Ay = 0

      (( x1 * F ) + ( D * Lab ) + ( D * L bc + D * L cd )

Cy = -------------------------------------------------------------------

                                      ( L ab + L bc )

Cy = 1.3 x 10³ k-N

<em><u>Support Ay:</u></em>

Since ∑ F = 0,           A + C - F - D = 0

                                   A = F  + D - C

                                  Ay = 200 k-N

4 0
2 years ago
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