distance traveled by a uniformly accelerated bike is given as

here we know that



now we will have from above equation


so it will cover the total distance of 300 m
Answer:
1.60 g
Explanation:
From the attached file below:
we can deduce that:

The distance traveled by 2 s will be:
x = vt
x = 20 m/s × 2 s
x = 40 m
The length is quarter of the circle with radius r,
so; if 2 πr = 4 x
Then radius (r) will be:

r = 25.5 m
The centripetal acceleration can be expressed as:

so;

a = 15.7 m/s²
the magnitude of the acceleration experienced by your unfortunate passengers in terms of acceleration due to gravity is then determined by the equation:



∴ The magnitude of the acceleration experienced by your unfortunate passengers during the turn = 1.60 g
Given data:
Volume of calcite (V) = 15 cm³,
mass of calcite (m) = 40.5 g,
find the
density of calcite (ρ) = ?
density is defined as " it is the amount of matter of an object in a given volume". Simply it is the ratio of matter in an object to its volume. The unit of density is kg/m³ in SI system or g/cm³ in CGS system.
Mathematically,
density ( ρ) = mass/volume
= m/V g/cm³
= 40.5 g/15 cm³
= 2.7 g/cm³
Hence, the density of calcite is <em>2.7 g/cm³ </em>
The object is moving with constant speed means there is no change in speed Hence the acceleration is 0
Where, u is initial speed,
v is final speed
t is time taken and
a is acceleration
a = ( v-u) /t
a =(0)/t because u=v
a=0
Therefore, Acceleration is 0