Properly input current above 40 voltage or 100 for example elecrical fan machine is used to perform a task, work output is always more than work
Answer:
h = 20 m
Explanation:
given.
height, h = 10 m
Potential energy at 10 m = 50 J
Kinetic energy at 10 m = 50 J
maximum height the ball will reach, H = ?
Total energy of the system
T E = 50 J + 50 J
T E = 100 J
now,
A h = 10 m
P E = m g h
50 = m g x 10
mg = 5 ..............(1)
at the top most Point the only Potential energy will be acting on the body.
now, TE = Potential energy
100 = m g h
5 h = 100
h = 20 m
hence, the maximum height reached by the ball is equal to 20 m.
Explanation:
Average power = change in energy / change in time
P = ΔE / Δt
P = (½ mv²) / t
P = (½ (0.825 kg) (0.620 m/s)²) / (0.021 s)
P = 7.55 Watts
Answer:
Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W
Explanation:
As we know that the current in the circuit at given instant of time is
i = 2.0 mA
R = 10 k ohm
now we know by ohm's law
so voltage across the capacitor + voltage across resistor = V
Now we know that
here rate of change in energy of the capacitor is given as
Answer:
612000 C
Explanation:
Current, I, is given as the rate of flow of charge, that is:
I = Δq / Δt
where q = electric charge
t = time taken
This implies that:
Δq = I * Δt
The battery rating is 170 Ampere-hours, therefore:
Δq = 170 * 1 hour
But 1 hour = 3600 seconds;
=> Δq = 170 * 3600 = 612000 C
The total charge that the battery can provide is 612000 C.
