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3 years ago

Of the following, where would we most likely find the most abundant storage of water?

Chemistry

2 answers:

mafiozo [28]3 years ago

7 0

It would be D) The Hydrosphere

antoniya [11.8K]3 years ago

5 0

Answer: D the hydrosphere

Explanation:

A hydrosphere can be define as the total amount of water present on planet earth. A planet's hydrosphere can include water in the form of vapor, liquid and ice. On Earth, the liquid water exists on the surface in the form of rivers, oceans and lakes. The hydrosphere exhibit the highest concentration of water as compared to the other spheres of the earth.

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In a coffee-cup calorimeter, 100.0 g of H2O and 100.0 mL of 1M HCl are mixed. The HCl had an initial temperature of 44.6 C and t

Hatshy [7]

Answer:

Exothermic reaction for the HCl, endothermic reaction for the water

$2803.28\ \text{J}$

Explanation:

Heat was lost by HCl as its temperature lowered, so it was an exothermic reaction for the HCL.

Heat was gained by water as its temperature increased, so it was an endothermic reaction for the water.

m = Mass of water = 100 g

c = Specific heat of water = $4184\ \text{J/kg}^{\circ}\text{C}$

$\Delta T$ = Change in temperature of water = $(31.3-24.6)^{\circ}\text{C}$

Heat is given by

$Q=mc\Delta T\\ =0.1\times 4184\times (31.3-24.6)\\ =2803.28\ \text{J}$

Heat gained by water is $2803.28\ \text{J}$ .

5 0

3 years ago

One method for preparing pure iron from Fe2O3 is by reaction with carbon monoxide.Fe2O3(s)+CO(g)→Fe(s)+CO2(g) How many moles of

larisa [96]

Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

Explanation:

Given data:

Mass of Fe₂O₃ = 122 Kg ( 122×1000 = 122000 g)

Moles of CO = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Number of moles of Fe₂O₃:

Number of moles = mass/ molar mass

Number of moles = 122000 g /159.69 g/mol

Number of moles = 764 mol

Now we will compare the moles of Fe₂O₃ with CO.

Fe₂O₃ : CO

1 : 3

764 : 3×764 =2292 mol

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

6 0

3 years ago

Using the periodic table, choose the more reactive nonmetal.<br> Te or o

Alex17521 [72]

Te is the correct ok is this

6 0

3 years ago

The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure

Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate $\Delta H_{vap}$ of the reaction, we use clausius claypron equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = vapor pressure at temperature $T_1$

$P_2$ = vapor pressure at temperature $T_2$

$\Delta H_{vap}$ = Enthalpy of vaporization

R = Gas constant = 8.314 J/mol K

1) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =363 K

$T_2$ = final temperature =373 K

$P_2=1 atm, P_1=?$

Putting values in above equation, we get:

$\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]$

$P_1=0.69671 atm \approx 0.6970 atm$

The vapor pressure at temperature 363 K is 0.6970 atm

2) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

$T_1$ = initial temperature =373 K

$T_2$ = final temperature =383 K

$P_1=1 atm, P_2?$

Putting values in above equation, we get:

$\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]$

$P_2=1.4084 atm \approx 1.410 atm$

The vapor pressure at 383 K is 1.410 atm

8 0

3 years ago

Terry heats two different masses of substance A to different temperatures, and measures the amounts of both carbon dioxide and w

Naddika [18.5K]

Answer:

This experiment is uncontrolled because two different masses of substance A are used.

Explanation:

A controlled experiment is a structured experiment aimed at testing a particular observation or observations. The setup of a controlled experiment helps to determine the reason why a particular observation occurs and what must have led to it.

In the experiment highlighted above, different masses of a substance were used, they were heated to different temperatures. The set up does not show any correlation between the masses of substances heated and the temperatures. It is even difficult to try to predict the hypothesis for this kind of experimental set up. All the variables in play can best be assumed to be independent of one another.

5 0

3 years ago

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