3 years ago

Of the following, where would we most likely find the most abundant storage of water?

Chemistry

2 answers:

mafiozo [28]3 years ago

7 0

It would be D) The Hydrosphere

antoniya [11.8K]3 years ago

5 0

Answer: D the hydrosphere

Explanation:

A hydrosphere can be define as the total amount of water present on planet earth. A planet's hydrosphere can include water in the form of vapor, liquid and ice. On Earth, the liquid water exists on the surface in the form of rivers, oceans and lakes. The hydrosphere exhibit the highest concentration of water as compared to the other spheres of the earth.

You might be interested in

Do two objects with the same mass always have the same volume

Vika [28.1K]

Only if they have the same mass.

5 0

3 years ago

Activity/Exercises: Kobe has been living in a coastal barangay for 30 years. Recently, he noticed that during high tides, water

Akimi4 [234]

The sea water during high tides enters inland.
It harms the soul.
It makes the soul salty.
which makes hard to survive for a plant.
It harms the atmosphere too

6 0

2 years ago

The brass cube has a mass of 67.2 grams. Each side is 2 cm long. What is the density of the brass cube? A) 2.8 g/cm 3 B) 3.15 g/

frutty [35]

The answer is D. 9.45 g/cm

4 0

2 years ago

The atomic mass of an atom can be found by

sashaice [31]

The answer to this question is A

8 0

3 years ago

Calculate the number of milliliters of 0.440 M KOH required to precipitate all of the Fe2+ ions in 187 mL of 0.692 M FeSO4 solut

EleoNora [17]

Answer:

588.2 mL

Explanation:

FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)

First we calculate how many Fe⁺² moles reacted, using the given concentration and volume of FeSO₄ solution (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):

moles = molarity * volume

187 mL * 0.692 M = 129.404 mmol Fe⁺²

Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:

129.404 mmol Fe⁺² * $\frac{2mmolKOH}{1mmolFeSO_4}$ = 258.808 mmol KOH

Finally we calculate the required volume of KOH solution, using the given concentration and the calculated moles:

volume = moles / molarity

258.808 mmol KOH / 0.440 M = 588.2 mL

6 0

2 years ago