Answer:
V₂ = 50.93 L
Explanation:
Initial volume, ![V_1=43.1\ L](https://tex.z-dn.net/?f=V_1%3D43.1%5C%20L)
Initial temperature, ![T_1=24^{\circ} C=24+273=297\ K](https://tex.z-dn.net/?f=T_1%3D24%5E%7B%5Ccirc%7D%20C%3D24%2B273%3D297%5C%20K)
Final temperature, ![T_2=78^{\circ} C=78+273=351\ K](https://tex.z-dn.net/?f=T_2%3D78%5E%7B%5Ccirc%7D%20C%3D78%2B273%3D351%5C%20K)
We need to find the final volume of the gas. The relation between the volume and the temperature is given by :
![\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L](https://tex.z-dn.net/?f=%5Cdfrac%7BV_1%7D%7BT_1%7D%3D%5Cdfrac%7BV_2%7D%7BT_2%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7BV_1T_2%7D%7BT_1%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7B43.1%5Ctimes%20351%7D%7B297%7D%5C%5C%5C%5CV_2%3D50.93%5C%20L)
So, the final volume of the gas is 50.93 L.
Answer:
The empirical formula simply states the ratios of the elements that make up the molecule, while molecular formulas specify the amounts of each element exactly, not just giving the ratio. Let's take ethane (C2H6) as an example.
15 because atomic no. is the number of protons
Answer:
165.0 grams
Explanation:
The law of conservation of mass tells us that the mass of the reactants will be equal to the mass of the products. Therefore, if we begin with 165.0 grams of mass, that is how much there will be at the end in the products, even if it's in different forms.
The liquid part of a homogeneous mixture is most often than not the a. solvent
This depends on the type of homogeneous mixture at hand. For a liquid-solid homogeneous mixture, the liquid works as the solvent. For a gas-liquid homogeneous mixture, the liquid often works as the solvent as well. However, for a liquid-liquid homogeneous mixture, the liquid acts as both the solute and solvent.