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Zanzabum
3 years ago
8

Calculate the volume of 2.5×10-4 moles of h2

Chemistry
1 answer:
sattari [20]3 years ago
3 0
At STP : volume is 22.4 L

1 mole H₂ -------------> 22.4 L
2.5 x 10⁻⁴ moles -----> ?

v = 2.5 x 10⁻⁴ * 22.4 / 1

v = 
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jasenka [17]

Ok, I will help you answer but it is very hard to read could you enlarge it first?

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5 0
3 years ago
The half life of radium-226 is 1600 years. If you have 200 grams of radium today how many grams would be present in 8000 years?
Sveta_85 [38]

Answer:

Half life is the time taken by a radio active isotope to reduce by half of its original amount. Radium-226 has a half life of 1602 years meaning that it would take 1602 years for a mass of radium to reduce by half.

Number of half lives in 9612 years = 9612/1602 = 6 half lives

New mass = Original mass x (1/2)n where n is the number of half lives.

Therefore, New mass= 500 x (1/2)∧6

                                 = 500 x 0.015625

                                 = 7.8125 g

Hence the mass of radium after 9612 years will be 7.8125 grams.

Explanation:

3 0
3 years ago
Read 2 more answers
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lapo4ka [179]

Answer:

And what is your question

Explanation:

3 0
4 years ago
Why did you have to form a diastereomeric salt from one of the enantiomers of ibuprofen? Choose two Group of answer choices It i
aleksklad [387]

Answer:

Correct answers: 2 and 3

Explanation:

1- correct would be: Isolation of ibuprofen is not dangerous, but it is necessary because only one enantiomer has effect on interaction with biologic <em>diana</em>

<em>2: Correct! This property of diastereomeric salts (differing solubilities) is really useful for the isolation of the original enantiomers</em>

<em>3: Correct! we can only observe their properties, like polirized light rotation or separation in an assimetric column for chromatography.</em>

4: correct would be: diastereomeric salts do not rotate light, they have lost the property of anantiomers that originated them

8 0
3 years ago
A 100. ml portion of 0.250 m calcium nitrate solution is mixed with 400. ml of 0.100 m nitric acid solution. what is the final c
pshichka [43]
<span>Answer: Moles Ca(NO3)2 = 100 x 0.250 / 1000 = 0.025 Ca(NO3)2 >> Ca2+ + 2NO3- Moles NO3- = 2 x 0.025 = 0.05 Moles HNO3 = 400 x 0.100 / 1000 = 0.04 Total moles = 0.05 + 0.04 = 0.09 Total volume = 500 ml = 0.500 L M = 0.09 / 0.500 = 0.18</span>
6 0
4 years ago
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