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Zanzabum
3 years ago
8

Calculate the volume of 2.5×10-4 moles of h2

Chemistry
1 answer:
sattari [20]3 years ago
3 0
At STP : volume is 22.4 L

1 mole H₂ -------------> 22.4 L
2.5 x 10⁻⁴ moles -----> ?

v = 2.5 x 10⁻⁴ * 22.4 / 1

v = 
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Calculate the pH of a 0.0224M HCl solution.
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Answer: 1.65

Explanation:

For a 0.0224M HCl solution the concentration of the hydrogen ions,

[H+] = is 0.0224 mol/L (i.e. 0.0224 M)

pH = −log[H+]

Substituting H+ = 0.0224 into the equation

pH = - log[0.0224]

pH = 1.649

pH = 1.65

6 0
3 years ago
Why would you not expect to find fossils in metamorphic and igneous rocks?
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Answer:

igneous rocks are made from molten,and therefore rarely have fossils in them.Metamorphic rocks are squished,put under pressure,and get heated to the extreme,so it's very rare for fossils to survive in these conditions.

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3 years ago
Which salt shows the least solubility change when the temperature is increased from 0 to 100 c?
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4 0
3 years ago
Read 2 more answers
What is the ph of a solution that results from mixing 25 ml of 0.15 M hcl to 25 ml of 0.52 m nh3?
BartSMP [9]

Answer:

7.00

Explanation:

When the solutions are mixed, the HCl dissociates to form the ions H+ and Cl-. The ion H+ will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H+ to 1 mol of Cl-, and 1 mol of H+ to 1 mol of NH3 to 1 mol of NH4+.

First, let's find the number of moles of each one of them, multiplying the concentration by the volume:

nH+ = 0.15 M * 25 mL = 3.75 mmol

nNH3 = 0.52 M * 25 mL = 13 mmol

So, all the H+ is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.

5 0
3 years ago
A container of argon with a volume of 22 ml has a pressure of 101.0 kPa.
Alexeev081 [22]

Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, V_1=22\ ml

Initial pressure, P_1= 101.0\ kPa

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

PV=k\\\\P_1V_1=P_2V_2

P_2 is final pressure

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa

So, new pressure is 44.4 kPa.

6 0
2 years ago
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