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fomenos
2 years ago
9

in 1990, the men's singles winner of the us. open tennis tournament has his serves clocked at 127 mi/hr. How fast must a 56.6 g

tennis ball travel to have a de Broglie wavelength equal to that of a photon of green light (5400 A)?
Chemistry
1 answer:
Naddika [18.5K]2 years ago
3 0

This problem is providing information about the mass of a tennis ball, 56.6 g (0.0566 kg) and asks for the velocity it will have to equal the wavelength of green light, which is 5400 A or 540 nm (5.4x10⁻⁷ m). Thus, after doing the math, the result is 2.17x10⁻²⁶ m/s.

<h3>Broglie's wavelength:</h3>

In this case, we recall the formula of the Broglie's wavelength as shown below:

\lambda =\frac{h}{mv}

Whereas lambda is the wavelength, h is the Planck's constant, m the mass and v the speed; thus, we solve for the speed according to the question:

v =\frac{h}{m\lambda}

<h3>Calculations:</h3>

Then, we just plug in the numbers we were given to get the answer:

v =\frac{6.626x10^{-34} kg*\frac{m^2}{s} }{0.056kg*5.4x10^{-7}m}\\\\v=2.17x10^{-26}m/s

Learn more about Broglie's wavelength: brainly.com/question/5440536

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Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

<u>Structure of H2S :</u>

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these  6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4  are non- bonding  and present as lone - pair

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There are 2-Lone pair on S in H2S (look at the image attached)

<u>Structure of H2S :</u>

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron  are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>

<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S  shifts way from lone pair</em></u>

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3 years ago
If a system is left to change spontaneously, in what state will it end?
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Answer:

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A gas that was cooled to 200 Kelvin has a volume of 65.8 L. If its initial volume was 132.4 L, what was its initial temperature?
Mandarinka [93]

Answer:

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Explanation:

<u>Given the following data;</u>

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Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

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Substituting the values into the formula, we have;

T_{1} = \frac {65.8 * 200}{132.4}

T_{1} = \frac {13160}{132.4}

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