3.
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Answer:
1.68 mol Ca(NO₃)₂
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Compounds
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 275 g Ca(NO₃)₂
[Solve] mol Ca(NO₃)₂
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Ca: 40.08 g/mol
[PT] Molar Mass of N: 14.01 g/mol
[PT] Molar Mass of O: 16.00 g/mol
Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂