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Anastaziya [24]
3 years ago
9

What’s the greatest common factor of 12x^2+9x^3-6x^4

Mathematics
1 answer:
VikaD [51]3 years ago
7 0

12x^2+9x^3-6x^4\\\\LCD(12,\ 9,\ 6)=3\\\\LCD(x^2,\ x^3,\ x^4)=x^2\\\\12x^2=(3x^2)(4)\\9x^3=(3x^2)(3x)\\-6x^4=(3x^2)(-2x^2)\\\\GCF\ of\ 12x^2+9x^3-6x^4\ is\ equal\ \boxed{3x^2}\\\\12x^2+9x^3-6x^4=(3x^2)(4+3x-2x^2)

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Ayuda es para hoy :C
olga55 [171]

Answer:

busca cymath.com

Step-by-step explanl

4 0
3 years ago
Subtract 12h+1 from 34h+4 . what is the answer? a.−1/4h+5 b.1/4h+5 c.−1/4h d.1/4h+3
Lemur [1.5K]

Answer:

D

Step-by-step explanation:

We would like to solve:

(3/4h + 4) - (1/2h + 1)

This is equivalent to:

3/4h + 4 - 1/2h - 1

First, combine like terms; that is, combine the terms with h in them and combine the terms without h in them:

3/4h - 1/2h + 4 - 1

The common denominator for 3/4 and 1/2 is 4, so:

3/4h - 1/2h = 3/4h - 2/4h = 1/4h

Put this back in:

1/4h + 4 - 1

1/4h + 3

The answer is thus D.

<em>~ an aesthetics love</em>

8 0
3 years ago
A year has four seasons. What is the probability that a day chosen at random will be in the spring?
mestny [16]

Answer:

1/4; 25%

Step-by-step explanation:

if a year has four seasons we can say that there are 4 possibilities

spring appears once

this means that the probability that a day chosen at random will be in spring would be 1 out of 4

or 25%

6 0
2 years ago
The graph below shows the function f(x)=x-3/x2-2x-3. Which statement is true?
BARSIC [14]
1. Domain.

We have x^2-2x-3 in the denominator, so:

x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\&#10;(x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}

So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.

2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
6 0
3 years ago
Read 2 more answers
Aidan writes numbers on his ten fingers as 5, 7, 9, 11, 13, 15, 16, 19, 22, 23. What is the probability of picking an even numbe
faltersainse [42]
It would be 2/10, or 1/5, since two out of the 10 numbers are even. 2/10 simplifies to 1/5, since there is 1 for every 5 numbers.

We could turn this into a percentage by dividing 1 by 5, which gives us 0.2. Then we can multiply by 100 to get 20.

So, our probability of choosing an even number is:
2/10
OR
1/5
OR
20%

Hope I could help!
6 0
3 years ago
Read 2 more answers
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