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lys-0071 [83]
3 years ago
13

I need help on this word problem!

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0
Width be X,  length is X+15

area of garden = x(x+15)
area of sidewalk =  x(x+15) - (x-4)(x+11) = 632

X^2 + 15X - X^2 - 7X + 44 = 632
8X = 632-44 =588

X= 73.5  >> WIDTH  and LENGTH = 88.5

HOPE IT HELPED

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Simplify the expression.
Naddika [18.5K]

Answer:

3

Step-by-step explanation:

((7x-4)^2) - (7x-4)(7x-4) + 3

(7x-4)(7x-4) is 7x-4^2

So its (7x-4)^2 - (7x-4)^2 + 3

(7x-4)^2 cancel out.

Answer is 3

6 0
2 years ago
a parking garage has 6 levels. Each level has 15 row. Each row has the same number of parking spaces. there are 2,250 parking sp
Mandarinka [93]
To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.

Equation

A = Parking spots per row


A = 2,250 Divided by(6 levels times 15 rows)

A= 2,250 Divided by 90


A = 25

The correct answer is 25 parking spots per row

To check this answer we can do

25 spots per row, Times 15 rows per level, Times the total amount of levels (6)

= the total amount of parking spots

25*15*6= 2,250

True


This confirms this answer as correct. Hope this helps.
6 0
2 years ago
What is a good estimate for this angle measurement?
ycow [4]
C. 75 degreesssssss:)
7 0
1 year ago
Read 2 more answers
Find the length of the unknown side. Round your<br> answer to the nearest tenth.
Oliga [24]

Answer:

20

Step-by-step explanation:

25^2=15^2+x^2. x=20

3 0
3 years ago
Identify the range of the function. A) (2, 8) B) [2, 8] C) (−5, 9) D) [−5, 9]
Ivanshal [37]

Answer:

The answer is "Option A"

Step-by-step explanation:

The domain is the collection of the value, which belongs to the separate variable (horizontal axis). So, to find a region with a graph, it must search for the function, which starts and end. And at all these levels we are searching at x-values.  

Its starting point is (2,9) and the ending point is (8,3).  Therefore, x= 2 to x=8 is the domain.

5 0
3 years ago
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