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adell [148]
4 years ago
14

Problem 3

Chemistry
1 answer:
prisoha [69]4 years ago
7 0

Answer:

774.265 kJ

Explanation:

Given an endothermic reaction in which 4 moles of production of ammonia requires 1170 kJ amount of energy . each mole of ammonia corresponds to 17grams. which means that 68 grams of ammonia production requires 1170 kJ amount of energy .

we are asked to find out the heat energy assosiated with the production of 45gms of ammonia  let us calculate the heat energy assosiated with per gram production of ammonia that is one gram of ammonia synthesis reqires \dfrac{1170}{68} amount of energy .Then 45 gms require 45\times \dfrac{1170}{68} amount of energy which is equal to 774.265kJ

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How is an analogy different from a metaphor
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3 0
4 years ago
2ca(s)+o2(g) → 2cao(s) δh∘rxn= -1269.8 kj; δs∘rxn= -364.6 j/k
Alinara [238K]

Gibbs free energy change for the reaction at 29°C.  is equal to -1378.93 KJ.

<h3>What is Gibbs's free energy?</h3>

Gibbs free energy can be described as the enthalpy of the system minus the product of the temperature and entropy.

If the chemical reaction can be carried out under constant temperature ΔT = 0:

ΔG = ΔH – TΔS

The above equation is known as the Gibbs-Helmholtz equation.

ΔG > 0 non-spontaneous and endergonic and ΔG < 0 spontaneous and exergonic, ΔG = 0 is representing equilibrium.

Given the ΔS = -364 J/K, ΔH = -1269.8 KJ, T = 29°C = 29 + 273 = 302 K

ΔG = - 1269 - 302 × 364

ΔG =  -1269 KJ - 109.93 KJ

ΔG =  - 1378.93 KJ

Learn more about Gibbs's free energy, here:

brainly.com/question/13318988

#SPJ1

Your question is incomplete, most probably the complete question was,

2Ca(s)+O₂(g) → 2CaO(s)

ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K

For this problem, assume that all reactants and products are in their standard states.

Calculate the free energy change for the reaction at 29°C.

6 0
2 years ago
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