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gulaghasi [49]
2 years ago
5

• Explain what causes the water to move through the cycle.

Chemistry
1 answer:
Tatiana [17]2 years ago
5 0

Answer:

Evaporation and gravity cause water to move through the water cycle.

Explanation:

Evaporation turns liquid water into a gas, and brings it up into the atmosphere, where the gas condenses into frozen water molecules, which stick to each other. When a clump of water molecules gets too heavy, gravity pulls them down to the surface as precipitation. Depending on the temperature, the frozen water droplets may melt, or stay frozen.

Gravity brings precipitation to the ground.

Water has to heat up from high temperature, from either the sun or another heat source, to change the form from gas to liquid.

Water vapor must get to a certain temperature of cold to freeze, causing it to condense from a gas to liquid.

Thermal energy causes evaporation of water, which allows the water to be reprecipitated once again.

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Opposing reactions are constantly occurring at equal rates

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3 years ago
2. Calculate the mass of K in 90g of KOH​
ValentinkaMS [17]

KOH = 90g

KOH = 57 g/mol

K = 40g/mol

57g/mol contains 90 g

40g/mol will contain?

= 63.15 g

The mass of K is 63.15g

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Quick! <br>I need to know <br>about how<br>old is the <br>earth!?​
Salsk061 [2.6K]

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3 years ago
How many moles of N2 are need to fill a 35 L tank at standard temperature and pressure?
Tems11 [23]

1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure. Details about moles can be found below.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

At STP;

  • T = 273K
  • P = 1 atm
  • R = 0.0821 Latm/molK

1 × 35 = n × 0.0821 × 273

35 = 22.41n

n = 35/22.41

n = 1.56mol

Therefore, 1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure.

Learn more about number of moles at: brainly.com/question/14919968

#SPJ1

4 0
2 years ago
What is the ∆G for the following reaction between O3 and O2? 3O2(g) 2O3(g) Given: O3: ∆H = 285.4 kJ ∆S = -137.14 J/K)
Natali [406]
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)

I’m going to assume 0 degrees Celsius.
At 0 C (273 K):

dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ

The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.

This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
6 0
3 years ago
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