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san4es73 [151]
3 years ago
10

Find solution of the linear equation y = 2/3x + 1/3

Mathematics
2 answers:
GaryK [48]3 years ago
8 0
Y=2/3x+1/3
0=2/3x+1/3
-1/3=2/3x
-1=2X
-0.5=X
Assuming this is what you meant when you wrote find the solution
ankoles [38]3 years ago
6 0

Answer:

3/3=1

Step-by-step explanation:


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8 0
3 years ago
Answer qn in attachment​
leva [86]

Answer:

\implies \dfrac{ -4x+7}{2(x-2) }

Step-by-step explanation:

The given expression to us is ,

\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}

Now take the LCM as ( x - 1 ) and Simplify , we have ,

\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}

Simplifying further , we get ,

\implies \dfrac{ -4x+7}{2(x-2) }

Hence the second option is correct .

4 0
3 years ago
How can I calculate a square root without guess and check?
Darina [25.2K]
By multiplying the same numbers.

2*2=4 *4 square root is 2

3*3=9 *9 square root is 3

4*4=16 *16 square root is 4

5*5=25 *25 square root is 5

Try this, maybe it will work :)
3 0
3 years ago
Exponents of Zero<br> Simplify x^0, where <br> x does not equal 0
densk [106]

Answer:

  1

Step-by-step explanation:

Any non-zero value raised to the zero power is 1.

  x^0 = 1

7 0
3 years ago
students were asked to simplify the expression . two students' work is given. student a step 1: step 2: step 3: 1 tan2 θ step 4:
Whitepunk [10]

Student B is wrong , student A is correct in simplifying the expression .

Expression B must be simplified to cot θ .

Formulas to be used are :

1 - sin^{2} θ = cos^{2}θ

 1 - cot^{2}θ = tan^{2}θ .

Since , location of error is step 3 , we will start from there

[ ( 1 - sin^{2}θ ) / sin θ ] / cos θ    = [ ( 1 - sin^{2}θ ) / sin θ ] * [ 1 / cos θ ]

                          = ( 1 - sin^{2}θ ) / ( sin θ * cos θ )

               = cos^{2} θ / ( sin θ * cos θ )

                   = cot θ .

To know more on trigonometry follow link :

brainly.com/question/24349828

#SPJ4

Since , the question is incomplete we assume it to be :

6 0
2 years ago
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