Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and
is the density of the string
Given T = 600N and
= 0.015 g/cm = 0.0015kg/m

The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
I don’t know the answer i just need the points
<span>1200 meters is less than 1 kilometer
</span>is false
Answer:
6400 W (or) 6.4 KW
Explanation:
Formula we use,
→ P = I²R
Let's solve for the power of device,
→ P = I²R
→ P = (8)² × 100
→ P = 64 × 100
→ [ P = 6400 W ]
Hence, the power is 6400 W.
It will be
d=m/v
=10/2
=5g/ml