Answer:
Explanation:
Hello,
In this case, since the hockey puck was moving at 34 m/s and suddenly stopped (final velocity is zero) in 7 seconds, we can first compute the acceleration via:
In such a way, we can compute the displacement via:
Best regards.
The component of weight(
mg) that is responsible for the motion of boxes on ramp is:
Where m = mass of the boxes.
g = Acceleration due to gravity = 9.8
= The angle the ramp makes with the ground. In this case it is 30°.
Since the frictional force is:
μ*N.
Where,
μ = Frictional Coefficient
N = Normal to the ramp =
Therefore, the frictional force becomes =
= μ*
Apply Newton's second law we would get:
- μ*
=
=>
=
μ
-- (A)
Now according to equation of motion:
Where x = 5.8m
= 0
= 0
= 10.24
Plug in the value in the above equation you would get:
= 1.1328
Plug in
in equation (A) and solve for
μ, you would get,
μ = 0.4439
Answer: 9m
Explanation:
Our given:
Acceleration- 5m/s^2
Time- 3.6 seconds
Use the equation d = 1/2 • a • t^2
d = 1/2 • 5m/s^2 • 3.6 secs
d = 2.5m/s^2 • 3.6 secs
d = 9m
I hope this is correct
<em>F</em> = 153 N
Explanation:
Let us define first our directional convention. Anything pointing up or to the right is considered positive and anything pointing down or to the left is considered negative. Now let's look at the components and :
= 350 N - 200 N = 150 N
= 180 N - 150 N = 30 N
The magnitude of the resultant force <em>F</em> is given by
To find the direction , we use
or