How many mL is an espresso?
One shot of espresso is generally about 30–50 ml (1–1.75 oz), and contains about 63 mg of caffeine (3). Important point: The “golden ratio” for espresso is this: a single shot is 30 to 44 mL (1 to 1.5 ounces) of water and 7 grams of coffee
Answer:
Equilibrium quantity = 5
Equilibrium price = 40
Explanation:
given:
p = -x²-3x+80
p = 7x+5
For the equilibrium quantity the price from both the functions will be equal
thus, we have
-x² - 3x + 80 = 7x+5
⇒ x² +3x + 7x + 5 - 80 = 0
⇒x² + 10x - 75 = 0
now solving for x
x²- 5x + 15x -75 = 0
x(x-5) + 15(x-5) = 0
therefore, the two roots of the equation are
x = 5 and x = -15
since the quantity cannot be in negative
therefore, the equilibrium quantity will be = 5
now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation
thus,
p = -(5)² -3(5) + 80 = 40
or
p = 7(5) + 5 = 40
The tendency of an object to resist a change in motion is called inertia.
Answer:
The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.
Explanation:
From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.
And for the acceleration of both spools, we mention the net force.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.
With the net force and mass, for each spool equal, from
ΣF = ma, we get that a = ΣF/m
Meaning that the acceleration of the identical spools is equal also.
Hope this Helps!
Answer : The specific heat of unknown sample is,
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of unknown sample = ?
= specific heat of water =
= specific heat of copper =
= mass of unknown sample = 72.0 g = 0.072 kg
= mass of water = 203 g = 0.203 kg
= mass of copper = 187 g = 0.187 kg
= final temperature of calorimeter =
= initial temperature of unknown sample =
= initial temperature of water and copper =
Now put all the given values in the above formula, we get
Therefore, the specific heat of unknown sample is,