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3 years ago

12

Terry, a 70-kilogram tailback, runs through his offensive line at a speed of 7.0 m/sec. Jared, a 100-kilogram linebacker, runnin

g in the opposite direction at 6.0m/s, meets Jared head-on and “wraps him up.” What is the result of this tackle?

1 answer:

Vilka [71]3 years ago

4 0

Terry will be thrown back due to Jared's larger mass. Larger mass= larger inertia

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fenix001 [56]

Answer:

C

Explanation:

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3 years ago

What is the condition for distance travelled by a body is equal to displacement

Simora [160]

Answer:

<em><u>When</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>straight</u></em><em><u> </u></em><em><u>line</u></em><em><u>,</u></em><em><u> </u></em><em><u>it's</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>becomes</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>displacement</u></em><em><u>.</u></em><em><u> </u></em>

Explanation:

<em><u>Distance</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>actual</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>covered</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>displacement</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>covered</u></em><em><u>.</u></em>

<em><u></u></em>

<em><u>✌</u></em><em><u>Follow</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>❤</u></em>

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6 0

4 years ago

A 56.0 kg box hangs from a rope. what is the tension in the rope if: the box has vy = 5.30 m/s and is speeding up at 5.10 m/s2 ?

Minchanka [31]

T = tension force in the rope in upward direction

m = mass of the box attached at end of rope = 56 kg

W = weight of the box in downward direction due to gravity

a = acceleration of the box in upward direction = 5.10 m/s²

weight of the box is given as

W = mg

inserting the values

W = (56) (9.8)

W = 548.8 N

force equation for the motion of the box is given as

T - W = ma

inserting the values

T - 548.8 = (56) (5.10)

T = 834.4 N

5 0

3 years ago

The principle of horizontality is based on the observation that sediment usually accumulates in layers. How will you describe th

N76 [4]

The implication is that tilted sedimentary layers observed to day mist have been subjected to tectonic forces

8 0

3 years ago

Which of the following statements is FALSE?

Levart [38]

A thrust fault is a reverse fault with an extremely high dip (close to 90°). This is the false statement.

Answer: Option D

<u>Explanation:</u>

Faults are the fracture or fracture zone occurring on the rocks. These fractures can travel through the rocks leading to massive destruction. So, depending upon the direction of their travel, the faults can be classified as normal, reverse and strike slip fault. Also, the angle of dip along the fault is one of the important criteria for determining the type of faults.

There is dip-slip fault which has its movement along the vertical fault plane while the strike slip fault will be in horizontal direction. Similarly, an oblique fault will be acting in both vertical and the horizontal direction. So, the fourth statement related to thrust fault is false as in reverse fault or thrust fault the dip will be shallow and not high.

5 0

3 years ago