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Alexandra [31]
4 years ago
10

Suppose you were examining a pulsing radio signal from a stellar remnant in a distant part of the Milky Way. Knowing that ionizi

ed gas in intestellar space causes dispersion of the radio waves, what effect would you expect this to have on the signal?
Physics
1 answer:
Solnce55 [7]4 years ago
5 0

Answer:

- Time delta is associated with difference in wavelengths

Explanation:

When pulsating radio waves consisting of different wavelengths pass through the ionized gas in interstellar space, the fast oscillating radio waves travel relatively faster than the slowly oscillating radio waves. As a result radio waves get dispersed and there is a time difference between the radio waves with different wavelength when the pulses arrive.

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How do you calculate force?
DIA [1.3K]
Force (N) = mass (kg) × acceleration (m/s²)
6 0
4 years ago
An object moving north with an initial velocity of 14m/s accelerates 5m/s squared for 20 seconds. What is the final velocity of
Gemiola [76]

Since it moves 5 m/s faster every second, after 20 seconds it's moving 100 m/s faster than when it started speeding up.

If it was moving at 14 m/s when the acceleration began, it's moving at 114 m/s at the end of the 20 seconds.  Its velocity is <em>114 m/s North.</em>

That's 255 mph !

4 0
3 years ago
Coulomb's Law relates which of the following?
Maslowich

Answer:

The force between two charges and the distance separating them.

Explanation:

4 0
3 years ago
How much force is required (in Newton’s) to accelerate a 4-kg skateboard, along with its 46-kg rider, at 3m/s2?
Soloha48 [4]

Answer:150N

Explanation:

Total mass=mass of skate board + mass of rider

Total mass(m)=46kg + 4kg

Total mass(m)=50kg

Acceleration(a)=3m/s^2

Force(f)=mass x acceleration

Force=50 x 3

Force=150N

5 0
3 years ago
An 3-kg object is dropped from a height of 5 m. The rock has an impact speed<br><br> of
Andrews [41]

Answer:

The rock has an impact speed  of 9.9 m/s.

Explanation:

given information:

object's mass, m = 3 kg

height, h = 5 m

in this case, the potential energy is equal to the kinetic energy

PE = KE

mgh = \frac{1}{2} mv²

where

m = mass (kg)

g = gravitational constant (9.8 m/s²)

v = velocity (m/s)

so,

mgh = \frac{1}{2} mv²

gh = \frac{1}{2} v²

v² = 2gh

v = √2gh

  = √(2)(9.8)(5)

  = 9.9 m/s

6 0
4 years ago
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