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3 years ago

Response to an unconditioned stimulus that occurs naturally without learning is known as a(n) __________ response.

2 answers:

7 0

The answer is D. Unconditioned
The response to an unconditioned stimulus that occurs naturally without learning and involuntarily triggers reaction is known as an unconditioned response. For example, you smell your favorite food while being cook may make you instantly feel hungry.

damaskus [11]3 years ago

5 0

Answer:

the answer is c

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) is it possible for one component of a vector to be zero, while the vector itself is not zero?

Natalka [10]

The least number of component of a vector quantity is two. These are the x-component and the y-component.

The resultant vector, or vector as we refer to it in this item, can be calculated through the equation,
RV = sqrt ((Vx)² + (Vy)²)

From the equation, it can be noted that if we let Vx equal to zero,
RV = Vy

Similarly, if we let Vy be equal to zero then,
RV = Vx

Thus, it is still possible for the vector to become nonzero even if one of its components is zero.

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3 years ago

Is my answer correct? Please i need to know

Alexeev081 [22]

Yes. Your answer is correct. I hope you do well on the quiz or whatever it is.

5 0

2 years ago

Read 2 more answers

Match the technology that uses radio waves to the field in which it is used

Elden [556K]

Answer:

Naturally occurring radio waves are made by lightning or by astronomical objects. Artificially generated radio waves are used for fixed and mobile radio communication, broadcasting, radar and other navigation systems, communications satellites, computer networks and innumerable other applications.

Explanation:

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3 years ago

alculate the kinetic energies of (a) a 2.00×103-kg automobile moving at 100.0 km/h; (b) an 80.0-kg runner sprinting at 10.0 m/s;

zzz [600]

Answer:

(a) 7.72×10⁵ J

(b) 4000 J

(c) 1.82×10⁻¹⁶ J

Explanation:

Kinetic Energy: This can be defined energy of a body due to its motion. The expression for kinetic energy is given as,

Ek = 1/2mv²................... Equation 1

Where Ek = Kinetic energy, m = mass, v = velocity

(a)

For a moving automobile,

Ek = 1/2mv².

Given: m = 2.0×10³ kg, v = 100 km/h = 100(1000/3600) m/s = 27.78 m/s

Substitute into equation 1

Ek = 1/2(2.0×10³)(27.78²)

Ek = 7.72×10⁵ J

(b)

For a sprinting runner,

Given: m = 80 kg, v = 10 m/s

Substitute into equation 1 above,

Ek = 1/2(80)(10²)

Ek = 40(100)

Ek = 4000 J

(c)

For a moving electron,

Given: m = 9.10×10⁻³¹ kg, v = 2.0×10⁷ m/s

Substitute into equation 1 above,

Ek = 1/2(9.10×10⁻³¹)(2.0×10⁷)²

Ek = 1.82×10⁻¹⁶ J

8 0

3 years ago

When the distance between two charges is halved, the electrical force between them?

Llana [10]

If the distance between two charges is halved, the electrical force between them increases by a factor 4.

In fact, the magnitude of the electric force between two charges is given by:
$F= k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
$r'= \frac{r}{2}$
the magnitude of the force changes as follows:
$F'=k \frac{q_1 q_2}{r'^2}=k \frac{q_1 q_2}{( \frac{r}{2})^2 }=k \frac{q_1 q_2}{ \frac{r^2}{4} } =4k \frac{q_1 q_2}{r^2}=4 F$
so, the force increases by a factor 4.

3 0

3 years ago