Answer:
H = 45 m
Explanation:
First we find the launch velocity of the ball by using the following formula:
v₀ = √(v₀ₓ² + v₀y²)
where,
v₀ = launching velocity = ?
v₀ₓ = Horizontal Component of Launch Velocity = 15 m/s
v₀y = Vertical Component of Launch Velocity = 30 m/s
Therefore,
v₀ = √[(15 m/s)² + (30 m/s)²]
v₀ = 33.54 m/s
Now, we find the launch angle of the ball by using the following formula:
θ = tan⁻¹ (v₀y/v₀ₓ)
θ = tan⁻¹ (30/15)
θ = tan⁻¹ (2)
θ = 63.43°
Now, the maximum height attained by the ball is given by the formula:
H = (v₀² Sin² θ)/2g
H = (33.54 m/s)² (Sin² 63.43°)/2(10 m/s²)
<u>H = 45 m</u>
Answer:
D
Explanation:
he describes as he writes them down
3.13 m/s2
.
the formula for acceleration is as follows:
force/mass = acceleration
-
so 25/8 = 3.13
Answer:
Explanation:
You didn't last any of the variables. You have to list the variables to tell which are which.
Hello!
We can use the following equation for calculating power dissipated by a resistor:
P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)
Plug in the known values and solve.
